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IceJOKER [234]
3 years ago
8

3x sqaured-2x+3 (x=-4)

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer:

<h2> The answer is X= -4 </h2>

gdeygfegfcbfwhjvgfhbcdjhfbcfyunhjdsgfyrhcduyfhscbdyfhusdcnefdjryhed

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Help please! find the value of y​
elena-s [515]

Answer:

Step-by-step explanation:

Download pdf
7 0
3 years ago
You spend $4.50 on 5 pounds of apples. What is the unit rate in dollars per pound?
vredina [299]

Answer:

$0.90 per pound.

Step-by-step explanation:

4.50:5

5/5=1

4.50/5=0.90

5 0
3 years ago
Read 2 more answers
3v+4(v-2)= -29 solve for v​
Lesechka [4]

Answer:

v = -3

Step-by-step explanation:

1) Expand.

3v + 4v - 8 = -29

2) Simplify 3v + 4v - 8 to 7v - 8.

7v - 8 = -29

3) Add 8 to both sides.

7v = -29 + 8

4) Simplify -29 + 8 to -21.

7v = -21

5) Divide both sides by 7.

v = -21/7

6) Simplify 21/7 to 3.

v = -3

4 0
2 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
3 years ago
Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by
o-na [289]

Answer:

B. \frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

W = \frac{3}{25}

X = \frac{\sqrt{3}}{11}

Y = \frac{9}{100}

Z = \frac{\pi}{24}

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

W = \frac{3}{25}

W = 0.12

X = \frac{\sqrt{3}}{11}

Take square root of 3

X = \frac{1.73205080757}{11}

X = 0.15745916432

X = 0.16 --- approximated

Y = \frac{9}{100}

Y = 0.09

Z = \frac{\pi}{24}

Take π as 3.14

Z = \frac{3.14}{24}

Z = 0.13083333333

Z = 0.13  --- approximated

List out the results, we have:

W = 0.12    X = 0.16    Y = 0.09    Z = 0.13

Order from greatest to least, we have:

X = 0.16     Z = 0.13      W = 0.12       Y = 0.09

Hence, the order of arrangement is:

X = \frac{\sqrt{3}}{11}     Z = \frac{\pi}{24}      W = \frac{3}{25}      Y = \frac{9}{100}

i.e.

\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

6 0
3 years ago
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