Question

Find the approximate value of b in the triangle shown.131285​

Answer 1

Answer:

The side b is 5 units

Step-by-step explanation:

Given the two sides of triangle and one angle of triangle we have to find the remaining side of triangle.

a=12 units

c=10 units

∠B=24°

we have to find the side b of triangle ABC

By cosine law,

$\cos B=\frac{a^2+c^2-b^2}{2ac}$

$\cos 24^{\circ}=\frac{12^2+10^2-b^2}{2(12)(10)}=\frac{144+100-b^2}{240}$

$b^2=244-240\cos 24^{\circ}=24.7490901658$

$b=4.97\sim 5units$

Answer 2

Answer:

The answer is D. 5

Step-by-step explanation: