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Gala2k [10]
3 years ago
7

What is the square root of –16? –8i –4i 4i 8i

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

we know that

i^{2} =-1

we have

\sqrt{-16} =\sqrt{(-1)*(16)} =\sqrt{(-1)*(4^{2})}

substitute the value of i^{2}=-1 in the expression above

\sqrt{(-1)*(4^{2})}=\sqrt{i^{2}*4^{2}} \\ \\= 4i

therefore

<u>the answer is</u>

4i


tino4ka555 [31]3 years ago
6 0
The answer to your question is 4i.
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What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1
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The general equation for the vertical hyperbola is

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Julien threw x number of pitches at baseball practice. Jacob threw 1/5 fewer than that
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Solve the system of equations: <br> X+y+z=5<br> -3x-4y+4z=15<br> 2x-y-4z=-8
atroni [7]

Answer:

  (x, y, z) = (3, -2, 4)

Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

  z = 5 -(3 +(-2)) = 4

The solution is (x, y, z) = (3, -2, 4).

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Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

  \left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]

__

If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

  -3x -4y +4(5 -x -y) = 15   ⇒   -7x -8y = -5

  (-3x -4y +4z) +(2x -y -4z) = (15) +(-8)   ⇒   -x -5y = 7

This pair of equations can be solved for x and y in any of the usual ways. Using the second equation to substitute for x, for example, gives you ...

  -7(-5y -7) -8y = -5   ⇒   27y = -54   ⇒   y = -2

  x = -5(-2) -7 = 3

  z = 5 -(3) -(-2) = 4

_____

<em>Additional comment</em>

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

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2 years ago
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