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Gala2k [10]
3 years ago
7

What is the square root of –16? –8i –4i 4i 8i

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

we know that

i^{2} =-1

we have

\sqrt{-16} =\sqrt{(-1)*(16)} =\sqrt{(-1)*(4^{2})}

substitute the value of i^{2}=-1 in the expression above

\sqrt{(-1)*(4^{2})}=\sqrt{i^{2}*4^{2}} \\ \\= 4i

therefore

<u>the answer is</u>

4i


tino4ka555 [31]3 years ago
6 0
The answer to your question is 4i.
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