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3 years ago

5n(3n-n+8) slove it please

1 answer:

4 0

Hey there! :)

5n(3n - n + 8)

Simplify.

(5n × 3n) + (5n × -n) + (5n × 8)

Simplify.

(15n²) + (-5n²) + (40n)

Remove parenthesis

**Remember : a negative times a positive is always a negative, a positive times a positive is a positive, and a negative times a negative is a positive**

15n² - 5n² + 40n

Combine like terms.

(15n² - 5n²) + 40n

Simplify.

10n² + 40n → final answer :)

~Hope I helped!~

You might be interested in

Which is an equation in point slope form of the line that passes through the points 7,5 and -4,-1

Free_Kalibri [48]

Answer:

the second option is the correct one

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (7, 5) and (x₂, y₂ ) = (- 4, - 1)

m = $\frac{-1-5}{-4-7}$ = $\frac{-6}{-11}$ = $\frac{6}{11}$

Use either of the 2 points as (a, b)

using (- 4, - 1), then

y- (- 1) = $\frac{6}{11}$ (x - (- 4)), that is

y + 1 = $\frac{6}{11}$ (x + 4)

6 0

2 years ago

Nvm I got it figured out .

Lesechka [4]

Well thats really great

5 0

3 years ago

HELP ASAP WILL MARK BRAINLIEST:)

Genrish500 [490]

Answer:

Step-by-step explanation:

The ratio of the larger figure to the smaller figure is simplfying 30/12 to 5/2

Honest the 7/4 is just an educated guess because...yeah

8 0

2 years ago

17.

IrinaVladis [17]

Answer:

$32 + $0.25x < $50

Step-by-step explanation:

1.he buy a backpack for $32

2. he buys x amount of pencils. Each pencil cost 0.25. ($0.25x)

3. all of that is less than(<) $50

4 0

2 years ago

What is the completely factored form of f(x)=x^3-7x^2+2x+4

xxMikexx [17]

$Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)$

$Steps:$

$x^3-7x^2+2x+4$

$Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}$

$\frac{x^3-7x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}$

$\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4$

$\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

8 0

2 years ago