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babunello [35]
3 years ago
5

What are the rules to solving equations by multiplying or dividing?

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

In order to move a number that is multiplied or divided by the variable, make sure to inverse both sides! That means, if the number is multiplied, you divide it by both sides. If it's divided, you must multiply it by both side; steps so that you can apply them to harder equations.

Sorry if this didn't help! I hope it did though, good luck. <3

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vichka [17]

Solution is in image

7 0
3 years ago
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Compare and Contrast: Below are two equations. Solve each equation and compare the two solutions. Choose the statement that is t
grin007 [14]
Equation #1:
|2x - 3| = 17
The first solution is
2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
-2x = 17 - 3 = 14
x = -7
The solutions are x = 10 or x = -7.

Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5

Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
    FALSE
b. Equation @1 has more solutions than Equation #2.
    TRUE
c. Equation #1 has fewer solutions than equation #2.
    FALSE
d. None of the statements a,b, or c apply.
    FALSE

Answer: b.

5 0
3 years ago
Pls help! ASAP! I will mark Brainliest! If you give me a file or guess I will report you! ​
madam [21]

Answer:

the second and last one

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5 0
3 years ago
What is the cell doing during the Sphase of interphase?
Studentka2010 [4]

Answer:

Synthesis or replication of DNA

Step-by-step explanation:

You can remember that because synthesis starts with an S

3 0
3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
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