Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Given:
The matrix equation is:
To find:
The value of matrix C.
Solution:
Let 
. Then the given equation can be rewritten as
On substituting the values of the matrices, we get
Therefore, the correct option is C.
Answer:
4
Step-by-step explanation:
The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept. In our equation, y = − 7 x + 4 , we see that the y-intercept of the line is 4.
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Answer:
2/3
Step-by-step explanation:
slope =(y1-y2)/(x1-x2)
slope=(1-(-1))/(6-3)
slope =2/3
Answer:
Step-by-step explanation:
Given that a car mechanic rounds a car's weight to the nearest thousand
By rounding off to nearest 1000, we mean we look at the last three digits. If these digits are 500 or greater, then we round the thousands digit up, and if they are less than 500, then we round down, keeping the thousand's digit the same.
To simplify the above we can say the 100th digit if greater than or equal to 5, we round off the 1000th digit by 1 up otherwise leave it as it is
Example, 18765 is rounded off as 19000 while
15462 is rounded off as 15000
Here the answer after rounding off is 4000
This is possible if the weight was atleast 3500 because in this case he would round off to 4000 or highest 4499.
If 3499 or 4500 the rounding off would not have been 4000
So least number is 3500 and greatest number is 4499.
