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valentinak56 [21]
4 years ago
12

PLEASE HELP AND EXPLAIN! (3 different problems)

Mathematics
1 answer:
Margaret [11]4 years ago
5 0

Answer:

<em>a</em><em>}</em><em>4</em><em>/</em><em>3</em>

<em>b</em><em>}</em>

<em>c</em><em>}</em><em>-</em><em>1</em><em>/</em><em>4</em>

Step-by-step explanation:

a}4-c/4-(2+b)

putting the values of b and c n its place

4-(-4)/4-(2-4)

4+4/4-(-2)

8/4+2

8/6

4/3 or 1.33

b}IDK SORRY

c} y-x+5+y/4

-1-4+5-1/4

-6+5/4

-1/4

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Thats my question down there mates
Law Incorporation [45]

Answer:

x = 9

Step-by-step explanation:

A line segment parallel to a side of a triangle and intersecting the other 2 sides divides the 2 sides in proportion, that is

\frac{9}{72} = \frac{1}{8} = \frac{3x-20}{56} ( cross-  multiply )

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Musical megabytes How much disk space
alexdok [17]

Given:

Consider the file sizes (in  megabytes) for 18 randomly selected files on  Gabriel's mp3 player are shown in the below figure.

To find:

The outliers in the  distribution.

Solution:

We have, the given data set

2.4, 2.7, 1.6 , 1.3 , 6.2, 1.3, 5.6, 1.1, 2.2, 1.9, 2.1, 4.4, 4.7, 3.0, 1.9, 2.5, 7.5, 5.0

Arrange the data in ascending order.

1.1, 1.3, 1.3, 1.6, 1.9, 1.9, 2.1, 2.2, 2.4, 2.5, 2.7, 3.0, 4.4, 4.7, 5.0, 5.6, 6.2, 7.5,

Divide the data in 4 equal parts.

(1.1, 1.3, 1.3, 1.6), 1.9, (1.9, 2.1, 2.2, 2.4),( 2.5, 2.7, 3.0, 4.4), 4.7, (5.0,5.6, 6.2, 7.5)

It is clear that,

Q_1=1.9

Q_3=4.7

IQR=Q_3-Q_1

IQR=4.7-1.9

IQR=2.8

Now,

Interval=[Q_1-1.5IQR,Q_3+1.5IQR]

Interval=[1.9-1.5(2.8),4.7+1.5(2.8)]

Interval=[-2.3,8.9]

All the data values lies in the interval [-2.3,8.9]. Therefore, the given data set have no outliers.

7 0
3 years ago
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