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3 years ago

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Goal programming: a. Is not an iterative solution procedure. b. Requires the use of only hard constraints. c. Involves solving p

roblems containing a collection of goals that we would like to achieve. d. Requires firm RHS values of the constraints.

1 answer:

Elodia [21]3 years ago

5 0

Answer:

c. Involves solving problems containing a collection of goals that we would like to achieve.

Explanation:

To solve this question we first need to understand what Goal Programming is. Goal Programming is basically an optimization technique which aims to solve decision problems with multiplicity of objectives. It is an extension of linear programming. Hence the answer is C

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What must be the diameter of a cylindrical 120-m long metal wire if its resistance is to be 6.0 ω? the resistivity of this metal

Free_Kalibri [48]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ . Rearranging the above equation,

$A=\frac{\rho l}{R}\\ \frac{\pi d^2}{4}=\frac{\rho l}{R}\\ d=\sqrt{\frac{4\rho l}{\pi R}}$

Here $l=120, R=6, \rho=1.68(10^{-8})$ .

Substituting numerical values,

$d=\sqrt{\frac{4(1.68)(10^{-8}) (120)}{\pi (6)}}\\ d=0.0006541$

Te diameter of the wire is $0.6541 mm$

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4 years ago

Which of the following is the keyboard shortcut for saving a document?

Kryger [21]

Cntrl s
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3 years ago

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What does resonance result in?

marin [14]

“The vibrations of the aluminum force the air Column inside of the rod to vibrate at its natural frequency. The match between the vibrations of the air column and one of the natural frequencies of the singing rod causes resonance.”

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3 years ago

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A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro

fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

$Q=C\times V$

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = $C_1=2.81 \mu F=2.81\times 10^{-6} F$

Charge of first capacitor = $Q_1$

Voltage across first capacitor = $V_1=1220 V$

$Q_1=C_1V_1$

$Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C$

Capacitance of first capacitor = $C_2=6.61\mu F=6.61\times 10^{-6} F$

Charge of second capacitor = $Q_2$

Voltage across first capacitor = $V_2=560 V$

$Q_2=C_2V_2$

$Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C$

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

$Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C$

Total capacitance in parallel combination:

$C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F$

Potential across both capacitors = V

$V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V$

756.88 Volts will be the potential difference across each capacitor.

8 0

3 years ago

An object has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s.

taurus [48]

For the object that has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s we have:

1. The velocity of the object is 7.21 m/s.

2. The angle it makes with the horizontal is 33.7°.

1. The velocity of the object can be found as follows:

$v = \sqrt{v_{x}^{2} + v_{y}^{2}}$

Where:

$v_{x}$ : is the horizontal component of the velocity = 6 m/s

$v_{y}$ : is the vertical component of the velocity = 4 m/s

Hence, the <u>velocity is</u>:

$v = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(6 m/s)^{2} + (4 m/s)^{2}} = 7.21 m/s$

2. The angle it makes with the <u>horizontal </u>can be calculated with the following trigonometric function:

$tan(\theta) = \frac{v_{y}}{v_{x}}$

Where:

θ: is the angle it makes with the horizontal

Therefore, the <u>angle is</u>:

$\theta = tan^{-1}(\frac{v_{y}}{v_{x}}) = tan^{-1}(\frac{4}{6}) = 33.7$

You can learn more about the components of the velocity here: brainly.com/question/2285233?referrer=searchResults

I hope it helps you!

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3 years ago