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prohojiy [21]
3 years ago
7

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m

/s^2 . Ignore air resistance. A flea jumps straight up to a maximum height of 0.380 m. What is its initial velocity v0 as it leaves the ground?
How long is the flea in the air from the time it jumps to the time it hits the ground?
Express your answer in seconds to three significant figures.
Physics
1 answer:
EastWind [94]3 years ago
7 0

Answer:

Explanation:

Given

maximum height=0.380 m

initial velocity=v_0

H_{max}=\frac{v_0^2}{2g}

0.380=\frac{v_0^2}{2\times 9.81}

v_0=2.73 m/s

The time of flight will be t=\frac{2v_0}{g}

time to reach top +time to reach bottom will be same

t=\frac{2\times 2.73}{9.81}

t=0.556 s

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Answer: kinetic energy is Energy of motion.

Explanation:

4 0
3 years ago
A scientist wishes to generate a chemical reaction in his laboratory. The temperature values in his laboratory
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At the same temperature . . .

         <em>  Fahrenheit reading = (1.8 times Celsius reading) + 32</em> .

F = (1.8 x 232) + 32

F = 417.6 + 32

<em>F =  449.6°</em>
8 0
3 years ago
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A 330-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,110 A. If the conductor is copper
vodka [1.7K]

Answer:

t = 402 years

Explanation:

To find the number of year that electrons take in crossing the complete transmission line, you first calculate the drift speed of the electrons. Then, you use the following formula for the current in a wire:

I=nqv_dA  (1)

n: number of mobile charge carrier per volume = 8.50*10^28 e/m^3

q: charge of the electron = 1.6*10^-19 C

vd: drift velocity of electron in the metal = ?

A: cross sectional area of the wire = π r^2 = π (0.02m/2)^2 = 3.1415*10^-4 m^2

I: current in the wire = 1110 A

You solve the equation (1) for vd:

v_d=\frac{I}{nqA}=\frac{110A}{(8.50*10^{28}m^{-3})(1.6*10^{-19}C)(3.1415*10^{-4}m^2)}\\\\v_d=2.59*10^{-4}m/s

Next, you calculate the time by using the information about the length of the line transmission:

x=v_dt\\\\x=330km=330000m\\\\t=\frac{x}{v_d}=\frac{330000m}{2.59*10^{-4}m/s}=1,270,184,865s\\\\1,270,184,865s*\frac{1\ year}{3,156,107}=402.45\ years

hence, the electrons will take aproximately 402 years in crossing the line of transmission

6 0
3 years ago
A film of soapy water on top of a plastic cutting board has a thickness of 255 nm. What wavelength and color is most strongly re
Alona [7]

Answer:

the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

Explanation:

This is a case of reflection interference, we must be careful

* There is a 180º phase change when light passes from the air to the soap film (n = 1,339), but there is no phase change when passing from the pomp to the plastic (n = 1.3)

* the wavelength within the film is modulated by the refractive index

     λₙ =  λ₀ / n

if we consider these relationships the condition for constructive interference is

     2 t = (m + ½)  λₙ

     2t = (m + ½)  λ₀ / n

      λ₀ = 2t n / (m + ½)

we substitute the values

      λ₀= 2 255 10⁻⁹ 1,339 / (m + ½)

      λ₀  = 6.829 10⁻⁷ (m + ½)

let's calculate the wavelength for various interference orders

m = 0

       λ₀ = 6.829 10⁻⁷/ ( 0 +   ½ )

       λ₀ = 13.6 10⁻⁷

       it is not visible

m = 1

      λ₀ = 6,829 10⁻⁷/ (1 + ½)

       λ₀ = 4.55 10⁻⁷

      color blue

m = 2

      λ₀ = 6.829 10⁻⁷ / (2 + ½)

      λ₀ = 2,7 10⁻⁷

   it is not visible

therefore the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

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