Question

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m/s^2 . Ignore air resistance. A flea jumps straight up to a maximum height of 0.380 m. What is its initial velocity v0 as it leaves the ground?
How long is the flea in the air from the time it jumps to the time it hits the ground?
Express your answer in seconds to three significant figures.

Answer 1

Answer:

Explanation:

Given

maximum height=0.380 m

initial velocity=$v_0$

$H_{max}=\frac{v_0^2}{2g}$

$0.380=\frac{v_0^2}{2\times 9.81}$

$v_0=2.73 m/s$

The time of flight will be $t=\frac{2v_0}{g}$

time to reach top +time to reach bottom will be same

$t=\frac{2\times 2.73}{9.81}$

t=0.556 s