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hjlf
3 years ago
7

What is the relationship between a manipulated variable and a responding variable?

Physics
2 answers:
ipn [44]3 years ago
7 0
The manipulated variable is changed by the responding variable
Brut [27]3 years ago
4 0

Answer: The manipulated variable causes a change in the responding variable.

Explanation:

A manipulated variable is the variable which can be changed in an experiment. It is also called as independent variable. The effect of change of the manipulated variable can be observed on the responding variable. The responding variable is the variable which is the outcome of the experiment. It can be measured and recorded. It is also called as dependent variable.

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Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to
LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

v^2 = u^2 + 2ad

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph

5 0
3 years ago
A 20 kg block rests on a rough horizontal table. A rope is attatched to the block and is pulled with a force of 80 N to the left
Pani-rosa [81]

Given :

Mass of block , M = 20 kg .

Force applied , F = 80 N .

Acceleration of block , a=2.5\ m/s^2 .

To Find :

The coefficient is Kinetic force friction between the block and the table .

Solution :

We know , Force equation on block is given by :

F_{net }=F-\mu_k mg \\\\ma = F-\mu_k mg \\\\20\times 2.5 = 80 -\mu_k \times 20 \times 10\\\\\mu_k\times 200=30\\\\\mu_k=\dfrac{30}{200}\\\\\ mu_k=0.15

Therefore , coefficient is Kinetic force friction between the block and the table is 0.15 .

Hence , this is the required solution .

5 0
4 years ago
If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
Elina [12.6K]
The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

G \frac{m_1m_2}{d^2}

G is simply a given constant.

If we're at the surface of Eath, m_1 refers to the mass of the Earth, m_2 to the mass of whatever is on the surface of Earth, and d to the radius of Earth. 

Normally, we define a constant g to be equal to G \frac{M}{r^2}; in which M is the mass of Earth and r the radius of earth; g happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

W=mg

As you can see, weight is directly proportional to mass, more mass implies more weight.
8 0
4 years ago
Thanks + BRAINLIST <br><br> Please need correct answer asappp
garik1379 [7]
(A) Standing waves are created by two identical waves reflecting off each other

(B) a general definition of a wave interference is, when more than on wave meet and interact in the same medium

Hope this helps :)
3 0
3 years ago
Read 2 more answers
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
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