Answer:
![{x}^{2} + 4x - 30 = - 3x \\{x}^{2} + 7x - 30 = 0 \\ {x}^{2} - 3x + 10x - 30 = 0 \\ x(x - 3) + 10(x - 3) = 0 \\ (x - 3)(x + 10) = 0 \\ \boxed{x = 3} \\ \boxed{x = - 10}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%204x%20-%2030%20%3D%20%20-%203x%20%5C%5C%7Bx%7D%5E%7B2%7D%20%20%2B%207x%20-%2030%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20-%203x%20%2B%2010x%20-%2030%20%3D%200%20%5C%5C%20x%28x%20-%203%29%20%2B%2010%28x%20-%203%29%20%3D%200%20%5C%5C%20%28x%20-%203%29%28x%20%2B%2010%29%20%3D%200%20%5C%5C%20%20%5Cboxed%7Bx%20%3D%203%7D%20%5C%5C%20%20%5Cboxed%7Bx%20%3D%20%20-%2010%7D)
<h3>
<em><u>x=3 or x=-10</u></em> is the right answer.</h3>
Answer:
A
<em>Hope that helps!</em>
Step-by-step explanation:
Answer:
y-5x-13 (lmk if you want me to explain)
Step-by-step explanation:
Answer:
15/17
Step-by-step explanation:
Sine is
, and we see that the angle opposite of A is 15 while the hypotenuse is 17. Plug that into your formula and you get
.
The question is a bit ambiguous: you may mean
![\sqrt{3x+8}](https://tex.z-dn.net/?f=%5Csqrt%7B3x%2B8%7D)
or
![\sqrt{3x}+8](https://tex.z-dn.net/?f=%5Csqrt%7B3x%7D%2B8)
Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have
![3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}](https://tex.z-dn.net/?f=3x%2B8%5Cgeq%200%20%5Ciff%203x%5Cgeq%20-8%20%5Ciff%20x%5Cgeq%20-%5Cdfrac%7B8%7D%7B3%7D)
In the second case, you have
![3x\geq 0 \iff x\geq 0](https://tex.z-dn.net/?f=3x%5Cgeq%200%20%5Ciff%20x%5Cgeq%200)