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2 years ago

Solve for x show all work

Mathematics

2 answers:

a_sh-v [17]2 years ago

8 0

Answer:

x=4

Step-by-step explanation:

we know the ratio of left to right is 2:1 because 6:3=2:1

the horizontal lines are parallel, so the other set of numbers follows the same proportions

$x^{2} +2x+11=2(x+13.5)\\x^{2} +2x+11=2x+27\\x^{2} +2x-2x=27-11\\x^{2} =16\\x=\sqrt{16} \\x=4$

Marina86 [1]2 years ago

7 0

Answer:

x = 6•3 == 18

18² = 324

324 + 2 + 11 = 337

Step-by-step explanation:

Order of Operations; PEMDAS

Parentheses

Exponents

Multiplication & Division (Left to Right) (ex: 10x2÷5) You would do whatever comes left for Multiplication or Division.

Addition & Subtraction (Left to Right) (ex: 10-2+5) You would do whatever comes left for Addition & Subtraction.

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Solve this please quickly

Volgvan

Answer:

1. m∠B=110°

2. 560 cm3

3. Numerical data

4. 2000 cm3

5. 50%

Step-by-step explanation:

1. The explanation of part 1 is given in the attachment.

2. Given dimensions : 10 cm, 8 cm, and 7 cm.

Let Length of cuboid =10 cm

breadth/width of cuboid =8 cm

height of cuboid = 7cm

Volume of cuboid = length *width* height

=( 10 *8*7) cm3

=(560) cm3

3. Age, Birth date and weight are the types/examples of "Numerical Data" because these all are describe in terms of numeric values.

4. 1 liter = 1000 cm3 or 1 cm3 = 0.001 liter

1.5 liters =(1.5*1000) cm3 = (15*100) =1500 cm3

1 dm3 =1000 cm3

0.35 dm3 = (0.35*1000) cm3 = (35*10) cm3 =350 cm3

Given expression: 1.5 litre + 0.35 dm3 + 150 cm3 = cm3

1500 cm3 + 350 cm3 +150 cm3 = 2000 cm3

5. If A=(1/2)B, then B : A = 50 %

Ratio: B : A

B : (1/2) B

1: (1/2)

50 % (The value of A is half of the value of B)

Download docx

6 0

3 years ago

3x+5y=-3 x-5y=-5 show your work

frez [133]

We are given the equations 3x+5y=-3 and x-5y=-5.

Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.

3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8

The y terms cancel out since one is positive and one is negative. Now we can solve for x.

4x = -8

$\frac{4x}{(4)} = \frac{-8}{(4)}$

x = -2

Now plug -2 in for x in one of the original equations to find y.

(-2) - 5y = -5

-5y = -3

y = 3/5

Our answer as an ordered pair is (2, 3/5)

6 0

2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago

Tommy purchased a riding lawnmower with an original value of $2,500. If the value of the riding lawnmower decreases by $300 per

Eva8 [605]

Answer:

$1000.

Step-by-step explanation:

Let x represent number of years.

We have been given that Tommy purchased a riding lawnmower with an original value of $2,500. The value of the riding lawnmower decreases by $300 per year. We are asked to find the value of lawnmower after 5 years.

Since the value of the riding lawnmower decreases by $300 per year, so value of lawnmower decrease in 5 years would be 5 times $300.

The final value of lawnmower would be initial value minus value decreased in 5 years.

$\text{The value of the lawnmower after five years}=\$2500-\$300(5)$