Part A : Substitution
Elimination
Argumentated matrices.
Part B :
1. Substitution is a method of solving systems of equations by removing all but one of the variables in one of the equations and then solving that equation. This is achieved by isolating the other variable in an equation and then substituting values for these variables in other another equation.
2. Elimination is another way to solve systems of equations by rewriting one of the equations in terms of only one variable. The elimination method achieves this by adding or subtracting equations from each other in order to cancel out one of the variables.
3. Augmented matrices can also be used to solve systems of equations. The augmented matrix consists of rows for each equation, columns for each variable, and an augmented column that contains the constant term on the other side of the equation.
Part C :
7x +y = 14
5x + y = 4
X= 5 and y = - 21
Hope this Helps : )
Answer:
This is so easy
Let me explain:
first lets find out (f+g)(x)=-x+3x+5+x^2+2x=
x^2+4x+5 this is the equation of a parabola because we have x^2
so only the first graph shows us a parabola
which remains the right one.
Answer:
The unknown value is being subtracted from 226 is 160
Step-by-step explanation:
Long division setup showing an incomplete calculation
- 2 hundreds and 1 tens is written in the quotient
- 3200 is subtracted from 3426 to give 226
- An unknown value represented by a box is being subtracted from 226
so,
The dividend = 3426
The divisor = 16
2 hundreds means 200 and 1 tens means 10
∵ The quotient = 200 + 10 + x
∵ Dividend = divisor × quotient
∴ (16 × 200) + (16 × 10) + (16 × x) +remainder = 3426
∵ 16 × 200 = 3200
Subtract 3200 from the dividend
∴ 3426 - 3200 = 226
∵ 16 × 10 = 160
∴ 226- 160 = 66
⇒160is the unknown value
∵ 16 × x = 16x
∵ 66 - 16x = 0
∴ 66 = 16x
- Divide both sides by 16
∴ x = 4 and remainder = 2
∴ 3426 ÷ 16 = 200 + 10 + 4
∴ 3426 ÷ 16 = 214
∴ From the steps above the missing number subtracted from
226 is 160
The unknown value is being subtracted from 226 is 160
The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
Read more about system of linear equations at
brainly.com/question/14323743
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