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Agata [3.3K]
3 years ago
13

These triangles are NOT similar! Why not? Use calculations AND words to explain.

Mathematics
2 answers:
zlopas [31]3 years ago
4 0

Answer:

if ΔPQR ≈ ΔSTU =>

=> PQ/ST = PR/SU = QR/TU

9/7 = 12/8 = 15/10

9×8 = 7×12

72 = 84 (false)

=> ΔPQR ≠ ΔSTU

stepladder [879]3 years ago
4 0
They aren’t the same due to the fact that they have different length and size. They have different numbers and letters to show you that the triangles are not similar due to size.
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Find II 2e-3f II^2 assuming that e & f are unit vectors such that II e +f II=sqrt(3/2).
sergey [27]

<span>We are given that ||e|| = 1, ||f|| = 1. </span>

<span>Since ||e + f|| = sqrt(3/2), we have </span>
<span>3/2 = (e + f) dot (e + f) </span>
<span>= (e dot e) + 2(e dot f) + (f dot f) </span>
<span>= ||e||^2 + 2(e dot f) + ||f||^2 </span>
<span>= 1^2 + 2(e dot f) + 1^2 </span>
<span>= 2 + 2(e dot f). </span>

<span>So e dot f = -1/4. </span>

<span>Therefore, </span>
<span>||2e - 3f||^2 = (2e - 3f) dot (2e - 3f) </span>
<span>= 4(e dot e) - 12(e dot f) + 9(f dot f) </span>
<span>= 4||e||^2 - 12(e dot f) + 9||f||^2 </span>
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6 0
3 years ago
Find the cosine of angle B.
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\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

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9² = 12² + 15² - 2 (12) (15) cos (B)

81 = 144 + 225 - 360 cos(B)

81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

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Answer: Cosine B = 0.8

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\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

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12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

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Answer: Cosine Angle A = 3/5

4 0
3 years ago
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A deck has 52 cards
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