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ikadub [295]
3 years ago
5

What is the range of the function y=square root x+5 ?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

  all non-negative real numbers, [0, ∞)

Step-by-step explanation:

Replacing x in the parent function √x with (x+5) shifts the graph horizontally, but has no effect on the vertical extent of the graph. It still ranges from 0 to +∞.

The range of √(x+5) is [0, ∞).

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Read 2 more answers
Can anyone help me with this?
Viktor [21]
E. 1/2
With trig functions, multiple x values correspond with the same y value.
Using an initial x value (the principle value), we can find other x values for the same y value, this is what we are are being asked to find in this question.
There are slightly different ways to find these x values (also known as solutions) for each of the basic trig functions.
The x values are in degrees for the basic trig functions.
For cosine, the rule is as follows:
360 - principle value;
this will give what I, personally, like to think of as a secondary principle value (this value is not actually recognised as a secondary principle value, I just like to think of it as such). Anyway, all other solutions can the be found by adding or substrating any integer multiple of 360 to/from the PV and 'secondary PV'.

For your question:
cos60 = 1/2
60 is the x value (PV)
so...
360 - 60 = 300 is the 'secondary PV'
Just to be clear, this means that if I were to find the cos300, I would get 1/2.

That is sufficient for explaining the answer to this particular question but if you wanted to find any other solution, you would just have to do either:
60 + or - n(360)
or...
300 + or - n(360),
where n = any integer
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3 years ago
Are the following fractions proportional?? .4/.8 and .71/.4
Neporo4naja [7]

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yes they are

Step-by-step explanation:

see nobody answers correctly:)

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