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ikadub [295]
3 years ago
5

What is the range of the function y=square root x+5 ?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

  all non-negative real numbers, [0, ∞)

Step-by-step explanation:

Replacing x in the parent function √x with (x+5) shifts the graph horizontally, but has no effect on the vertical extent of the graph. It still ranges from 0 to +∞.

The range of √(x+5) is [0, ∞).

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F(x) =x^6-3x+9<br> g(x)=3x^3+2x^2-4x-9<br> Find (f-g)(x)
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Step-by-step explanation:

(f-g)(x)=

x ^{2}  - 3x + 9 - (3 {x}^{3}  + 2 {x}^{2}   - 4x - 9) =  \\ x ^{2}  - 3x + 9 - 3 {x}^{3}  - 2 {x}^{2}  + 4x  + 9 = \\  - 3 {x}^{3}  - x ^{2}  + x + 18

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Answer:

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Read 2 more answers
write the linear equation from the given information in slope intercept form passing through (-2,8) and perpendicular to y=2x+5​
Leto [7]

Answer:

y  =  -\frac{1}{2} x + 9

Step-by-step explanation:

Given parameters:

  Coordinates = (-2,8)

Equation of the line  y  = 2x + 5;

Unknown:

Linear equation of a line perpendicular = ?

Solution:

From the given expression, a line perpendicular will have a negative inverse of the slope given.

           y  = 2x + 5

Equation of a line  is y = mx + c;

y and x are the coordinates

  m is the slope

   c is the intercepts

    y  = 2x + 5 ;

 The slope is 2;

  A line perpendicular will have a slope of -\frac{1}{2}  

 Since y = 8 and x  = -2, let us find c;

     8  = 2 x -\frac{1}{2}  + c

    8 = -1 + c

     c  = 8+1 = 9

The equation of the line is;

       y  =  -\frac{1}{2} x + 9

7 0
3 years ago
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