From 2 Points:
2 answers:
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Answer: B
Begin by simplifying the given equation, so it's rearranged into standard form. Move all the terms onto one side, so they equal 0. This would result with -3x-9=0. Quadratic formula is (-b±√(b²-4ac))/(2a). Standard form follow this variable format:
+bx+c. Use the numbers that correspond with each variable to substitute them into the quadratic formula. This would be
(-(-3)±√(-3²-4(4)(-9)/2(4).
<u>Given</u>:
Given that the radius of the circle is 2 inches.
We need to determine the area of the remaining square.
<u>Area of a square:</u>
Given that each circle has a radius of 2 inches.
Then, the diameter of each circle is 4 inches.
Hence, the side length of the square is 2 × 4 = 8 inches.
The area of the square is given by
Thus, the area of the square is 64 square inches.
<u>Area of the four circles:</u>
The area of one circle is given by
Substituting r = 2, we have;
Thus, the area of one circle is 4π in²
The area of 4 circles is 4 × 4π =16π in²
Hence, the area of the 4 circles is 16π in²
<u>Area of the remaining square:</u>
The area of the remaining square is given by
Area = Area of the square - Area of four circles.
Substituting the values, we get;
Thus, the area of the remaining square is (64 - 16π) in²
Hence, Option c is the correct answer.