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oksano4ka [1.4K]
3 years ago
14

Let g(x) be the reflection of f(x)=x2+5 jn the x axis. what is a function rule for g(x)

Mathematics
1 answer:
Pie3 years ago
4 0
X axis
means y turns to -y
multiply whole thing by -1
g(x)=-(x^2+5)
g(x)=-x^2-5

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A blimp is 1600 meters high in the air and measures the angles of depression to two stadiums to the east of the blimp. if those
Sonja [21]

The two stadiums are 2,871 meters

A blimp    = point A

stadium 1  = point B

stadium 2 = point C

height of the blimp ,  AD = 1600

depression angle of stadium 1 , ∠y = 71.7°

depression angle of stadium 2 , ∠x = 25.2°

distance between the two stadiums  = d

So, it forms 2 triangles  ABD and ACD,

Using the trigonometric ratios,

tan θ = Altitude / Base

DC = AD × tan (90° - x)

= 1600 × tan( 90° - 25.2° )

= 1600 × cot(25.2°)

= 1600 × 2.13

DB = AD × tan (90° - y)

= 1600 × tan( 90° - 71.7° )

= 1600 × cot(71.7°)

= 1600 × 0.33

∴ d = DC - DB

     = 1600 * [ tan( 90° - 25.2° ) - tan( 90° - 71.7° ) ]

    = 2,871 meters

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brainly.com/question/9723082

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5 0
2 years ago
Identify the theorem or postulate that is related to the measures of the angles in the pair, and find the unknown angle measures
aleksley [76]

Angles formed when two parallel are intersected by a common transversal include, corresponding, alternate interior and exterior, same-side interior, and vertically opposite angles

The correct option is Same–Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

The reason the selection is correct is as follows:

The given angles are;

m∠1 = (30·x - 30)°. m∠5 = (40·x + 70)°

∠1, and ∠5, are located on the same side of the transversal and are both formed on the interior side of the parallel lines

Therefore, they are same–side interior angles

Same side interior angles theorem states that same side interior angles formed between parallel lines are supplementary

Therefore, we have;

m∠1 + m∠5 = 180°

Which gives;

(30·x - 30)° + (40·x + 70)° = 180°

(70·x + 40)° = 180°

70·x = 180° - 40° = 140°

x = \dfrac{140^{\circ}}{70} = 2^{\circ}

m∠1 = (30·x - 30)° = (30 × 2 - 30)° = 30°

m∠1 = 30°

m∠5 = (40·x + 70)° = (40 × 2 + 70)° = 150°

m∠5 = 150°

The correct option is therefore;

Same-Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

Learn more about parallel lines cut by a transversal here:

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