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WARRIOR [948]
3 years ago
11

Round to the nearest hundredth please answer I really need it

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0
<h3>Answer: 35.54 degrees</h3>

How I got this answer:

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 5/7

A = arctan(5/7)  .... apply the inverse tangent, same as arctangent

A = 35.5376778 ... make sure your calculator is in degree mode

A = 35.54 .... rounding to two decimal places

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Find the x- and y-intercepts of the graph of 7x + 6y = 21. State your answers as
Amanda [17]
To find the x-intercept, set y=0 and solve for x.
To find the y-intercept, set x=0 and solve for y.

7x+6y=21

x-int: y=0
7x+6(0)=21
7x=21
x=3

y-int: x=0
7(0)+6y=21
6y=21
y=21/6 or 7/2
5 0
3 years ago
Martina chose a random sample of 10 bags of candy from two different Brands, A and B. All bags in the sample are the same size.
weqwewe [10]

B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.

4 0
3 years ago
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Find the length of a diagonal of a square with sides 10in. long
Ghella [55]
Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
{x}^{2}  +  {x}^{2}  =  {10}^{2}
2 {x}^{2}  = 100
{x }^{2}  = 50
x =  \sqrt{50}
side of a diagonal=2 sqrt50
= 10 \sqrt{2}
cm......



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3 0
3 years ago
Read 2 more answers
Simplify by dividing negative three over eight divided by five over nine.
goblinko [34]

Answer:

\frac{-27}{40}

Step-by-step explanation:

First we need to write in correct form :

\frac{-3}{8}:\frac{5}{9}

We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.

So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)

\frac{-3}{8} *\frac{9}{5}

Now, multiply numerator by numerator, denominator by denominator :

\frac{-27}{40}

8 0
3 years ago
Read 2 more answers
A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0
3 years ago
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