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Kruka [31]
2 years ago
13

Anyone know this one?

Mathematics
1 answer:
Shalnov [3]2 years ago
5 0

Answer:

B) 2(3x^2+10x+15

Step-by-step explanation:

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Please include an explanation so I know how to do this. Thanks!
klasskru [66]
Hello there,


So we are trying to find out is the angle ∠BAC in degrees. 

So what we are going to do is. . .25- (2x-10)°.

That answer would be -2x+35.

So ∠BAC= -2x+35°.
Hope this helps.

~Jurgen

7 0
3 years ago
Read 2 more answers
Sin(5x) cos(3x)-1/2sin(8x) = sin(x) cos(x)
aleksandrvk [35]

Answer:

x=70

Step-by-step explanation:

7 0
3 years ago
Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.
jeka94

Answer:

x=4+2\sqrt{3}

x=4-2\sqrt{3}

Step-by-step explanation:

<u>Completing the square</u>

when  ax^2+bx+c=0

Given equation:

3x^2-24x+40=28

Subtract 40 from both sides:

\implies 3x^2-24x=-12

Divide both sides by 3:

\implies x^2-8x=-4

Add the square of half the coefficient of x to both sides:

(\frac{b}{2})^2=(\frac{-8}{2})^2=16

\implies x^2-8x+16=-4+16

Factor the left side and simplify the right side:

\implies (x-4)^2=12

Square root both sides:

\implies x-4=\pm\sqrt{12}

Add 4 to both sides and simplify the radical:

\implies x=4\pm\sqrt{4 \cdot 3}

\implies x=4\pm\sqrt{4}\sqrt{3}

\implies x=4\pm2\sqrt{3}

5 0
1 year ago
What is the ratio of 2 soccer balls to 6 footballs
LiRa [457]
2 to 6 is the answer
5 0
3 years ago
Read 2 more answers
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
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