Thank you sooo much Maddi441
3x + 4y = 38 ( equation 1) ----> ×5
5x - 5y = -30 ( equation 2) ----> ×3
When you multiply eqn 1 by 5 you get, 15x + 20y = 190
And when you multiply eqn 2 by 3, you get, 15x - 15y = -90
Then you solve both equations by subtracting eqn 2 from eqn 1
15x + 20y = 190
15x - 15y = 90
Then 15x - 15x gets cancelled and 20y - (-15y) gives 35y and 190 - (-90) gives 280.
So that gives 35y = 280
y = 8
And when you replace y = 8 in any of the two equations, x = 2
AMOUNT DEPOSITED: $15k ($15,000)
INTEREST RATE PER YEAR: 0.07% (7%)
STEPS:
→Multiply the amount deposited ($15k) by the interest rate per year (7%).
15,000 * 0.07
= $1,050 (interest earned in 1 year)
→Multiply the interest earned from the first year ($1,050) by the amount of years that you want to calculate (3 years)
$1,050 * 3
=3,150 (interest earned in 3 years)
→ Add the interest earned (in 3 years, in this particular equation) to the amount that you deposited ($15k)
$15,000 + $3,150
=$18,150
FINAL ANSWER: $18,150
Answer:
im not sure but i think its 48
Step-by-step explanation:
if you divide the two you get 96. Divide that by the average rate number (2) and get 48.
Note: 20 weeks = 20/52 or 5/13 of a year.
Let E = effective rate of interest
E = [1 + (r/m)]^m - 1 where r is the nominal (annual ) advertised rate; m is the number of compounding periods/year.
Let r = 0.0275
Let m = 5/13
Plug into formula and do the math.
