There are 17 hops in a hop, a skip, and a jump.
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How to perform changes of units?</h3>
We have the relations:
- 1 skip = 4 hops.
- 1 jump = 3 skips.
How many hops are in a hop, a skip and a jump?
So we have:
1 hop + 1 skip + 1 jump.
First, using the second relation we rewrite:
1 hop + 1 skip + 3 skips = 1 hop + 4 skips.
Now, using the first relation:
1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.
There are 17 hops in a hop, a skip, and a jump.
If you want to learn more about changes of units:
brainly.com/question/9032119
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Answer:
5,040 different passwords are possible
Step-by-step explanation:
Assuming that 4-digit means using only numeric values.
This is a permutations problem.
n = number of values used with number values only this is 10
r = the number used in each case without repeating in this case 4
nPr = n! / (n - r)!
nPr = 10! / (10-4)!
nPr = 10! / 6!
The ! means factorial. For example 4! = 4 x 3 x 2 x 1 = 24
A quick hack for dividing factorials is to use cancelling.
10! / 6! = 10 x 9 x 8 x 7 (because 6 to 1 are cancelled by 6!)
= 5040
Answer:
X=2
Step-by-step explanation:
3x²+2x-7=2x+5
-2x -2x
3x²-7= 5
+7 +7
3x² = 12
3 3
= 
X=2
Let d be distance travelled when they are level , and t = time that nora took to get level with mason
for Nora
6 = d/t
d = 6t
for Mason
5 = d / (t + 35)
d = 5 ( t + 350
so 6t = 5(t + 35)
solve for t
