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kobusy [5.1K]
3 years ago
7

What is an equation of the line that passes through the points (1, -7) and (-4, 8)?

Mathematics
1 answer:
melomori [17]3 years ago
3 0
<h2>Answer:    y + 7  =  -3 (x - 1)</h2>

Step-by-step explanation:

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                       

                                          =  (- 7 - 8) ÷ ( 1 - (- 4))

                                         =    - 15  ÷  5

                                         =  - 3

We can now use the point-slope form to write the equation for this line:

        y - y₁ = m(x - x₁) where (x₁ , y₁) = (1, -7)

             y - (-7) =  -3 ( x  -  1)

              y + 7  =  -3 (x - 1)

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y = 3 ^ x

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x = 3 ^ y

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y = log_ {3} (x)

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f ^ {- 1} = log_ {3} (x)

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3 years ago
Please show work for both problems
sukhopar [10]

(1) The value of x is 25

(2) The measure of ∠CBD is 60°

Explanation:

(1) The given two angles are vertical angles. Since, vertical angles are equal, we can add the two angles to determine the value of x.

Thus, we have,

5x+15=6x-10

Subtracting 5x from both sides, we have

15=x-10

Adding 10 to both sides , we have,

25=x

Thus, the value of x is 25.

(2) It is given that the measure of ∠ABC = (x+7)° and ∠CBD = (2x+14)°

Since, these two angles are supplementary angles and supplementary angles add upto 90°

Thus, we have,

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Thus, substituting the value of x in ∠CBD = (2x+14)° to determine its value.

2x+14=2(23)+14=46+14=60

Thus, the measure of ∠CBD is 60°

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3 years ago
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