Answer:
34
Step-by-step explanation:
You will divide eveything by 6
you will end up with
Hello,
As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}
Answer C
Step-by-step explanation:
question 8 answer = -4
questions 9 answer = -18
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Answer:
2(x + y)² - 9( x + y ) -5 = 0
⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0
⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0
taking (x + y -5 ) common ,
⇒(x + y -5 )[2(x + y) + 1] =0
⇒(x + y -5)(2x + 2y +1) =0
hope , you got this