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Anna11 [10]
3 years ago
15

What volume of 6.0M NaOH is required to make 300.0mL of 0.500M NaOH?

Chemistry
1 answer:
g100num [7]3 years ago
4 0

Answer:

Option B. 25mL

Explanation:

Step 1:

Data obtained from the question:

Molarity of stock solution (M1) = 6M

Volume of stock solution needed (V1) =..?

Molarity of the diluted solution (M2) = 0.5M

Volume of diluted solution (V2) = 300mL

Step 2:

Determination of the volume of the stock solution needed.

Using the dilution formula, we can easily find the volume of the stock solution needed as follow:

M1V1 = M2V2

6 x V1 = 0.5 x 300

Divide both side by 6

V1 = (0.5 x 300) /6

V1 = 25mL

Therefore, 25mL of 6M NaOH is needed.

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100 POINTS. PLEASE HELP!!! born haber cycle problem b. need to find enthalpy of atomization of Mn. I attempted it but I keep get
Rom4ik [11]

Answer:

The Born Haber cycles is an adaption of Hess’s law to calculate lattice enthalpy from other data

The lattice enthalpy cannot be determined directly. We calculate it indirectly by making use of changes

for which data are available and link them together in an enthalpy cycle the Born Haber cycle

Enthalpy of lattice formation

The Enthalpy of lattice formation is the standard enthalpy

change when 1 mole of an ionic crystal lattice is formed

from its constituent ions in gaseous form. Na+

(g) + Cl- (g)  NaCl (s) [Latt H = -787 kJ mol-1

]

Enthalpy of lattice dissociation

The Enthalpy of lattice dissociation is the standard enthalpy

change when 1 mole of an ionic crystal lattice form is

separated into its constituent ions in gaseous form.

NaCl (s)  Na+

(g) + Cl- (g) [Latt H = +787 kJ mol-1

]

Generally Lattice Enthalpy refers to the enthalpy change when a lattice is made from gaseous ions.

Some exam boards refer to the opposite process at tim

Explanation:

7 0
2 years ago
If and electron is heated or electrified, it will give off light energy as it moves from a lower to a higher electron energy lev
rodikova [14]

Answer:

False

Explanation:

When electrons move from lower to higher electron energy level they absorb the energy. When  they move from higher to lower energy level they emit energy.

3 0
3 years ago
Some solutes have large heats of solution, and care should be taken in preparing solutions of these substances. The heat evolved
OLga [1]

Answer:

Final temperature of water is 83.8°C

Explanation:

In 500.0mL of a 6.00M NaOH solution, there are:

0.5000L × (6.00mol NaOH/ L) = <em>3.00moles of NaOH</em>

As the heat involved in dissolution is 44.5 kJ/mol, when the solution is dissolved:

44.5kJ/mol × 3.00moles = 133.5kJ = 133500J

Using coffee-cup calorimeter equation:

q = m×C×ΔT

<em>Where q is heat, m is mass of water (500.0g), C is specific heat of water (4.186J/g°C) and ΔT is change in temperature</em>

<em />

133500J = 500.0g×4.186J/g°C×(X-20.0°C)

63.8 = (X-20.0°C)

83.8°C = X

<em>Final temperature of water is 83.8°C</em>

3 0
3 years ago
TWO QUESTIONS! NEED HELP PLEASEEE
castortr0y [4]

First question I believe is B

The second one is also B

I really hope it helped

8 0
4 years ago
the isotope 146c has a half life of 5730 years. what fraction of 146c in a sample with mass ,m, after 28650 years
defon

Answer:

3.1% is the fraction of the sample after 28650 years

Explanation:

The isotope decay follows the equation:

Ln[A] = -kt + Ln[A]₀

<em>Where [A] could be taken as fraction of isotope after time t, k is decay constant and [A]₀ is initial fraction of the isotope = 1</em>

<em />

k could be obtained from Half-Life as follows:

K = Ln 2 / Half-life

K = ln 2 / 5730 years

K = 1.2097x10⁻⁴ years⁻¹

Replacing in isotope decay equation:

Ln[A] = -1.2097x10⁻⁴ years⁻¹*28650 years + Ln[1]

Ln[A] = -3.4657

[A] = 0.0313 =

<h3>3.1% is the fraction of the sample after 28650 years</h3>

<em />

3 0
3 years ago
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