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3 years ago

What volume of 6.0M NaOH is required to make 300.0mL of 0.500M NaOH?

Chemistry

1 answer:

g100num [7]3 years ago

4 0

Answer:

Option B. 25mL

Explanation:

Step 1:

Data obtained from the question:

Molarity of stock solution (M1) = 6M

Volume of stock solution needed (V1) =..?

Molarity of the diluted solution (M2) = 0.5M

Volume of diluted solution (V2) = 300mL

Step 2:

Determination of the volume of the stock solution needed.

Using the dilution formula, we can easily find the volume of the stock solution needed as follow:

M1V1 = M2V2

6 x V1 = 0.5 x 300

Divide both side by 6

V1 = (0.5 x 300) /6

V1 = 25mL

Therefore, 25mL of 6M NaOH is needed.

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Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

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A gas cylinder of volume 5.00 l contains 1.00 g of ar and 0.500 g of ne. the temperature is 275 k. find the partial pressure of

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