Answer:
Mass of solute, LiCl = 8.60g
Mass of solvent, H₂O = 57.4 g
Explanation:
Solution density = Solution mass / Solution volume
1.0736 g/mL = 66 g / Solution volume
66 g / 1.0736 g/mL = 61.47 mL
We know solution's molarity, so with this data we know that 3.30 moles of solute (LiCl) are contained in 1 L of solution (1000 mL)
Let's make the rule of three:
1000 mL contain 3.30 moles of LiCl
61.47 mL would contain (61.47 mL . 3.30 mol) / 1000 mL = 0.203 moles of LiCl
We can find out the mass of solute with the moles. Let's do it!
0.203 mol . 42.39 g/mol = 8.60 g of LiCl.
Total mass = Mass of solvent + Mass of solute
Let's find out the mass of solvent, to finish the problem
66 g = Mass of solvent + 8.60 g
66 g - 8.60 g = Mass of solvent → 57.4 g
