This is a probablity question
there are 3 slots, 26 letters of the alphabet
so in the first slot, we have 26 possible letters
2nd slot, we have 25 possible letters (we used one for the first slot)
3rd slot, we have 24 possible letters, (we used 2 for first and 2nd slot)
so in total, we have 26*25*24 or 15600 different 3 letter initials with no repeated letters
Answer:
This is not an equation. It is an expression, you can't solve for x in an expression
Answer:
Step-by-step explanation:
Here you go mate
Use PEMDAS
Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction
Step 1
-3(x-2)=9 Equation/Question
Step 2
-3(x-2)=9 Remove parenthesis
3x+6=9
Step 3
3x+6=9 Add -6
-3x=3
Step 4
−3x=3 Divide
answer
x=-1
Hope this helps
Answer:
y=5/7 x=31/7
Step-by-step explanation:
Make the x values the opposite of each other:
-2(x+5y=8)
-2x-10y=-16
2x+3y=9
Combine like terms and solve for y:
-7y=-5
y=5/7
Plug y in to find x.
x+5(5/7)=8
x+25/7=8
56/7-25/7=x
x=31/7
<span>You can use Heron's formula to solve this problem.
</span>

, where
A is the area;
a,b,с are the sides;
s<span> is the </span>semiperimeter<span> of the triangle
</span>

<span>According to conditions:
</span>a = x
b = x+1
с = 2x-1
<span>Calculate the semiperimeter:
</span>

<span>Now we can compose and solve the equation according to Heron's formula:
</span>

<span>As a result, x = 6 is your answer.
I hope this helped.</span>