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Ipatiy [6.2K]
3 years ago
14

The picture is my question.

Mathematics
2 answers:
Dominik [7]3 years ago
5 0
The second one because domain refers to x, and since at (-3,-4) the point is hollow, the sign should be < without the line under it
Soloha48 [4]3 years ago
5 0
The second option should be the correct answer.
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Establish the identity.<br> (2 cos 0-6 sin 0)² + (6 cos 0+2 sin 0)2 = 40
kogti [31]

Rewriting the left-hand side as follows,

(2\cos\theta-6\sin \theta)^2 +(6\cos \theta+2\sin \theta)^2\\\\=4\cos^2 \theta-24\cos \theta \sin \theta+36 \sin^2 \theta+36 \cos^2 \theta+24 \cos \theta \sin \theta+4 \sin^2 \theta\\\\=40\cos^2 \theta+40 \sin^2 \theta\\\\=40(\cos^2 \theta+\sin^2 \theta)\\\\=40

8 0
1 year ago
Long before iPhones that hold thousands of songs and play
Flauer [41]

Answer:

Do you mean an MP3 player?

Step-by-step explanation:

4 0
2 years ago
Fill in the table of values for the equation y = x + 2​
sweet [91]

Answer:

-3

2

5

Step-by-step explanation:

3 0
3 years ago
The estimated velocity v (in miles per hour) of a car at the end of a drag race is v=234 3√p/w (cube root) , where p is the hors
faltersainse [42]
Given that <span>v=234 3√p/w (cube root)
where </span><span> 
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour

p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity

v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
4 0
3 years ago
What is the product? 2x+8 x2 + 3x-4 x(x-4)(x-1) 20x+4) 2 (x+4)(x-4) 2x(x-1) 2x(x+4)​
guajiro [1.7K]

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

step by step

(2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x)+((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(4)

=−640x10+3840x9+4544x8−58904x7+91128x6−40608x5+128x4+512x3−2560x9+15360x8+18176x7−235616x6+364512x5−162432x4+512x3+2048x2

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

7 0
3 years ago
Read 2 more answers
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