Question

Solve by completing the square: x^2 + 3x - 9 = 0

Answer 1

Answer:

Step-by-step explanation:

x^2 + 3x - 9 =0

By comparing with the equation ax^2+bx+c = 0,

we get,

a = 1, b=3, c = -9

we know the formula for x is,

x = (-b±√(b^2 - 4ac))/2a

x = (-3±√45)/2

x = (-3±3√5)/2

x = (-3+3√5)/2, (-3-3√5)/2

Answer 2

Answer:

2 solutions. x = -3/2 + 3/2 * sqrt(5) and x = -3/2 + -3/2 * sqrt(5)

Step-by-step explanation:

Let's solve your equation step by step.

x^2 + 3x −9 = 0

For this equation: a=1, b=3, c=-9

1x^2 + 3x+ −9 = 0

Step 1: Use quadratic formula with a=1, b=3, c=-9.

x = (-b ± $\sqrt{b^2 - 4ac}$)/2a

x = (-3 ± $\sqrt{3^2 - 4(1)(-9)}$)/2a

x = (-3 ± $\sqrt{45}$)/2

x = -3/2 + 3/2 * sqrt(5) or x = -3/2 + -3/2 * sqrt(5)