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2 years ago

Please some help me or I’ll fail I need help ASAP

Mathematics

1 answer:

Ronch [10]2 years ago

4 0

Answer:

1cm

Step-by-step explanation:

from the scale we know that

1cm on the map is equal to 300cms on the ground

Below I have made a table and used the unitary method.

Distance on Map Distance on ground

1cm 300cm

let width be = x width = 3m = 300cm

hence

width = ( 1 ×300)/ 300 = 1cm

Hope this helps

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goldfiish [28.3K]

½ = v; multiply the divisor to remove the variable from the denominator.

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3 years ago

PLEASE HELP IN ONE MINUTE

marissa [1.9K]

Answer:

no solution

Step-by-step explanation:

x2-x1/y2-y1

8-5/-4+4= 3/0

3/0 = N/0 solution

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2 years ago

Which expression is equivalent to (<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D" id="TexFormula1" title="\sqrt[3]

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Answer:

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2 years ago

Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

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2 years ago

Calls to a customer service center last on average 1.4 minutes with a standard deviation of 1.7 minutes. An operator in the call

igomit [66]

Answer:

the expected total amount of time in minutes is 88.4

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The computation of the expected total amount of time in minutes is given below:

= Standard deviation × needed to answer calls each day

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2 years ago