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jek_recluse [69]
3 years ago
15

In a sale, there is 25% off all prices . all chair costs 90 pound in the sale

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

The answer is 120 pounds

Step-by-step explanation:

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Classify the model as exponential growth or exponential decay. Identify the growth or decay factor AND the percent of increase o
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See also brainly.com/question/8975313

The growth factor is 2.

The increase is (2 -1)*100% = 100% per period.
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Negativite eleven is less than negativte one
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False -11 is furter on the number line then -1
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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
3(5 +4) + 4 – 2 •4=<br><br> HELPPPP
Y_Kistochka [10]

Answer:

23

Step-by-step explanation: hope this helps

6 0
3 years ago
An airline weighed the carry-on luggage of all its
nikklg [1K]

Using the graph, it is found that 976 passengers had carry-on luggage that weighed less than 20 lb.

<h3>Graph:</h3>

The graph is not given in this problem, but an internet search indicates that the information it contains is as follows:

  • 120 passengers carry luggage of 4 lb or less.
  • 222 passengers carry luggage between 5 lb and 9 lb.
  • 378 passengers carry luggage between 10 lb and 14 lb.
  • 256 passengers carry luggage between 15 lb and 19 lb.
  • 90 passengers carry luggage between 20 lb and 24 lb.
  • 40 passengers carry luggage between 25 lb or more.

Hence, the number of passengers with luggage below 20 lb is:

120 + 222 + 378 + 256 = 976

976 passengers had carry-on luggage that weighed less than 20 lb.

A similar problem, also involving the use of graph, is given at brainly.com/question/25836450

7 0
2 years ago
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