H (x) = 5x^2+40x+64
y = (5x^2+40x+60) + 4
y = 5(x^2+8x+12) + 4
y = 5(x+2)(x+6) + 4
y-4 = 5(x+2)(x+6)
This means that the solutions, or where the parabola crosses the x-axis, are at x+2=0 and x+6=0, or x=-2, -6
So the midpoint of -2 and -6 is -4, the axis of symmetry is x=-4
Answer:
8 and 10
Step-by-step explanation:
Our first step is to set x as the other side length, and y as the hypotenuse. We get that 6 + x + y = 24, and x + y = 18. The area gives us that 6x = 24(2) = 48. We then divide both sides by 6 and we get x = 8. We have x = 8 so we plug that into the equation x + y = 18 and we get that y = 10. So the other side lengths are 8 and 10.
6x=10^= (*=0) is the answer
I can not see the picture?
Answer:
a) 5
b) 20
c) 28
d) 10
Step-by-step explanation:
a) 7-2=5
b) 2(7)+3(2)
= 14+6
= 20
c) 2(7)(3)= 28
d) (7-2)^2
= (14-4)
= 10