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3 years ago

In cooking class, Sofia measures a stick of butter. It is 13 centimeters long, 3 centimeters

Mathematics

2 answers:

Margarita [4]3 years ago

6 0

Answer:

117 cm³

Step-by-step explanation:

To calculate the volume of a Rectangular Prism, we must use the formula:

l×w×h=V.

In this case, l= 13, w= 3, and h= 3.

When these values are substituted in, we get:

13×3×3= 117 cm³

Alisiya [41]3 years ago

5 0

Answer: 117 centimeters

Step-by-step explanation:

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Write equations for the vertical and horizontal lines passing through the point , −1−8 .

icang [17]

Vertical line (when y = 0)
⇒ Equation : x = -1

Horizontal line (when x = 0)
⇒ Equation : y = -8

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Answer: x = -1, y = -8
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4 years ago

Order the numbers in each list from least to greatest. <br>0,|-14|, 13, -12, |-16|,17

Mrac [35]

Answer:

-12, 0, 13, [-14], [-16], 17

Step-by-step explanation:

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4 years ago

As a ship approaches the dock, it forms a 70 angle between the dock and the lighthouse. At the lighthouse, an 80 angle is formed

Trava [24]

Answer:

The distance from the ship to the dock is approximately 5.24 miles

Step-by-step explanation:

From the parameters given in the question, we have;

The angle formed between the dock and the lighthouse = 70°

The angle formed between the dock and the lighthouse at the ship = 80°

The distance between dock and the lighthouse = 5 miles (From a similar question online)

By sine rule, we have;

$\dfrac{a}{sin(A)} = \dfrac{b}{sin(B)} = \dfrac{c}{sin(C)}$

Therefore, we have;

$\dfrac{5}{sin(70^{\circ})} = \dfrac{The \ distance \ from \ the \ ship \ to \ the \ dock}{sin(80^{\circ})}$

$\therefore The \ distance \ from \ the \ ship \ to \ the \ dock = sin(80^{\circ}) \times \dfrac{5}{sin(70^{\circ})}$

$sin(80^{\circ}) \times \dfrac{5}{sin(70^{\circ})} \approx 5.24 \ mi$

Therefore;

The distance from the ship to the dock ≈ 5.24 miles

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3 years ago

Find f(g(x)) and g(f(x)) of f(x)=x^2-8, g(x)=2x-5

Zina [86]

$f(x)=x^2-8\\\\g(x)=2x-5\\\\f(g(x))\to\text{instead of x write the equation of the function g(x)}\\\\f(g(x))=(2x-5)^2-8=(2x)^2-2(2x)(5)+5^2-8\\\\=4x^2-20x+25-8=4x^2-20x+17\\\\\text{used}\ (a-b)^2=a^2-2ab+b^2$

$g(f(x))\to\text{instead of x write the equation of the function f(x)}\\\\g(f(x))=2(x^2-8)-5=(2)(x^2)+(2)(-8)-5=2x^2-16-5=2x^2-21$

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3 years ago

9. You are mailing a 21-pound item by parcel post. The total weight of an item and its packaging cannot be greater than 50 pound

Elza [17]

Answer:

Step-by-step explanation:

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3 years ago