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3 years ago

If the probability of a machine producing a defective part is 0.05, what is the probability of

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

0.1800 to 4 places of decimals.

Step-by-step explanation:

Using the Binomial formula

Probability = 10C5* (0.95)^95 * (0.05)^5

= 100! / 95!*5! * (0.95)^95 * (0.05)^5

= 0.1800178.

You might be interested in

Which set of numbers may represent the lengths of the sides of a triangle? (A) {2,5,9} (B) {6,6,7} (C) {6,4,2} (D) {7,8,1}

Olin [163]

Answer:

B {6, 6, 7}

Step-by-step explanation:

Which set of numbers may represent the lengths of the sides of a triangle? (A) {2,5,9} (B) {6,6,7} (C) {6,4,2} (D) {7,8,1}

For a given triangle with 3 sides, the sun of the length of any two sides must be greater Than the third side. This can be expressed mathematically as;

Let the side be ;

x, y and z

Then:

x > (y + z) or

y > (x + z) or

z > (x + y)

For A{2,5,9}

(2 + 5) < 9 (does not meet criteria)

For B {6,6,7}

(6 +6) > 7

(7 +6) > 6

Meets all criteria

For C {6,4,2}

(4 +2) is not greater Than 6 (does not meet criteria)

For D {7,8,1}

(7 +1) is not greater Than 8 ( does not meet criteria)

3 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = -4.9t^2

Sauron [17]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0

4 years ago

I need help please, anyone?!! I don’t know what I’m doing, please give explanation to your answer

Alla [95]

15% Of 2780 is 417

Convert 15% to a decimal (0.15) and multiply by 2780

0.15*2780= 417

Awnser: 417

7 0

3 years ago

Read 2 more answers

Help help help guys show you solution

Mars2501 [29]

Answer:

Step-by-step explanation:

1) y = 2x ----------(I)

x + y = 6 -----------(II)

Plug in y =2x in equation (II)

x + 2x = 6 {Add like terms}

3x = 6

x = 6/3

x = 2

Plugin x = 2 in (I)

y = 2*2

y = 4

Check:

LHS = x +y

= 2 + 4

= 6 = RHS

2)5x + 10y = 3 ------------(I)

x = (-1/2) y ------------(II)

Substitute x = (-1/2)y in (I)

$5*\frac{-1}{2}y + 10y = 3\\\\\frac{-5}{2}y+ \frac{10*2}{1*2}y = 3\\\\\frac{-5}{2}y+\frac{20}{2}y=3\\\\\frac{-5+20}{2}y = 3\\\\\frac{15}{2}y=3\\\\ y = 3*\frac{2}{15}\\\\ y = \frac{2}{5}$

Substitute y = (2/5) in equation (II)

$x = \frac{-1}{2}*\frac{2}{5}\\\\x = \frac{-1}{5}$

Check:

Substitute x and y value in equation (I)

$LHS = 5*\frac{-1}{5}+10*\frac{2}{5}\\\\ = -1 + 2*2\\\\ = -1 + 4\\ = 3 = RHS$

3) y - x = 3x + 2

y = 3x + 2 + x

y = 4x + 2 ---------------(I)

2x + 2y = 14 - y

2x + 2y +y = 14

2x + 3y = 14 ------------------(II)

Substitute y = 4x + 2 in equation (II)

2x + 3(4x +2) = 14

2x + 3*4x + 3*2 = 14

2x + 12x + 6 = 14

14x + 6 = 14

14x = 14 - 6

14x = 8

x = 8/14

x = 4/7

Substitute 'x' value in (I)

$y = 4*\frac{4}{7} +2\\\\y = \frac{16}{7}+2\\\\y= \frac{16}{7}+\frac{2*7}{1*7}\\\\y=\frac{16}{7}+\frac{14}{7}\\\\y=\frac{30}{7}$

Check:

 $LHS = 2x + 3y\\\\ = 2*\frac{4}{7}+3*\frac{30}{7}\\\\ = \frac{8}{7}+\frac{90}{7}\\\\=\frac{8+90}{7}\\\\=\frac{98}{7}\\\\=14 = RHS$ 

6 0

3 years ago

Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 12 h using both

Leokris [45]

Answer:

Jim's hose: 27 hours.

Bob's hose: 21.6 hours.

Step-by-step explanation:

Let t represent hours taken by Jim's hose.

Part of pool filled by Jim's hose in 1 hour would be $\frac{1}{t}$ .

We have been given that Bob's hose, used alone, takes 20% less time than Jim's hose alone. This means that Bob's hose take will take 80% time of Jim's hose that is $0.8t$ .