Answer:
the areas of these triangles are 83.2cm² and 46.8cm²
Step-by-step explanation:
1. If the triangles are similar and the ratio of the perimeter ois 4:3, then the areas are in the following ratio:
4²:3²
16:9
2. The sum of their areas is 65 cm², then, you can calculate the area of the larger triangle as following:
130(16/16+9)
130(0.64)
=83.2cm²
3. The area of the smaller triangle is:
130(9/16+9)
130(0.36)
46.8cm²
<u>Hope this help</u>s
.2 (simplified from 0.20)
2/10 (simplified from 20/100)
C. 7.2°F is warmer than 7.0°F but colder than 7.6°F.
So since -2, 0, 1 are the roots:
Therefore x = -2, x = 0 , x = 1
Implies that:
x = 2 x - 2 = 0
x = 0 x = 0
x = 1 x - 1 = 0
Therefore (x - 2)x(x - 1) = 0
(x - 2)(x - 1) = x(x - 1) - 2(x - 1) = x² - x - 2x + 2 = x² - 3x + 2
(x - 2)x(x - 1) = 0
(x - 2)(x - 1)x = 0
(x² - 3x + 2)x = 0
x*x² - x*3x + x*2 = 0
x³ - 3x² + 2x = 0
This is the polynomial with the least degree, because it possible for another polynomial with higher power to still have the same root.
x³ - 3x² + 2x = 0 is the polynomial.
I hope this helps.
