Use the graph of the function f to determine the given limit. Picture provided below

Mathematics

2 answers:

slamgirl [31]3 years ago

7 0

Answer:

a. 2

Step-by-step explanation:

Here we have to find when lim x ---> 2, what would be the value of f(x).

The value of f(x) is nothing y value in the graph.

From the given graph, we have to see the value of y, when x = 2

The value of y = 2, when x = 2 by looking at the graph.

Therefore, the answer is a. 2

Hope you will understand the concept.

Thank you.

elena-14-01-66 [18.8K]3 years ago

6 0

Answer:

Choice B..... The limit seems to be 8

Step-by-step explanation:

From the graph, the value of the function when x approaches 2 would be 8. The point (2, 2) is an undefined point or a point of discontinuity. Therefore, the limit can not be equal to 2. Nevertheless, there is a point marked by a dark circle (2, 8). this means that when x is 2 the value of the function is 8 even though the point does not lie on the straight line.

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Write the expression 2a+b in the form of a fraction with the given denominator. Check if the domain of the expression changed. I

Ymorist [56]

Answer:

See below

Step-by-step explanation:

I will assume the given denominator is 3a as there is nothing attached to the statement.

Lets first look at the domain of 2a+b. As it is a polynomial with unknowns a and b, we know it has its domain in all real numbers for both a and b as every polynomial does. For verifying it replace a and b by any real number you can think of.

Domain = a, b belonging to R

Now, if we divide 2a+b by 3a we will have:

(2a+b)/3a

As know we don not have a polynomial we cant state that the domain will still be all the real numbers for sure. We need to go further.

We have a fraction and as every fraction the denominator CAN'T be equal to 0, so 3a MUST be different to 0. This means that a MUST be different to 0. So, now our domain changes:

domain' = a, b belonging to R and a different to 0.

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3 years ago

What is the perimeter of quadrilateral ABCD?

alex41 [277]

Answer:

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