You draw a card from a standard deck of 52 cards. What is the probability of drawing a

Round 132,654 to the nearest ten thousand

______130,000_______

5 0

3 years ago

kaye has $2.80 in nickels and dimes. she has three timesas many dimes as nickels. how many nickels and how many dimes does she h

Vitek1552 [10]

8 nickels, because 8 (nickels) × 5 (worth) = 40
24 dimes, because 8 × 3 = 24 24 × 10 = 240
240 + 40 = 280

4 0

3 years ago

According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio

joja [24]

Answer:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

$p_v =P(t_{44}>2.73)=0.0045$

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=86.7$ represent the average life for the sample

$s=8.6$ represent the population standard deviation

$n=45$ sample size

$\mu_o =83.2$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 83.2$

Alternative hypothesis : $\mu > 83.2$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

Give the appropriate conclusion for the test

First we need to calculate the degrees of freedom given by:

$df=n-1=45-1=44$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{44}>2.73)=0.0045$

Conclusion

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0

3 years ago

Select the correct answer.

tensa zangetsu [6.8K]

Answer:

C.

Step-by-step explanation:

The similarity between these types of insurance is that neither type offers benefits unless you suffer a loss. In either type of insurance you would either need to lose your life or lose a piece of property. It is then that the insurance company will pay what the insurance contract states. Until such a time that the loss is incurred, the insurance does not provide any benefit to you or your family members.

6 0

3 years ago

4^3 x4^5<br> A.16^8<br> B.16x15<br> C.4^15<br> D.4^8

n200080 [17]

the answer is in the picture

8 0

3 years ago

Read 2 more answers