Answer:
D. All real numbers.
Step-by-step explanation:
This expression can have any real number assigned to x.
Answer:
hello your question is incomplete below is the missing parts
(a) A\ (A\B) = B\(B\A)
(b) A\ (BA) = B\(A\B)
answer : A\ (A\B) = B\(B\A) = always true
A\ (BA) = B\(A\B) = sometimes true and sometimes false
Step-by-step explanation:
(a) A\ (A\B) = B\(B\A). = ALWAYS TRUE
using de Morgan's law to prove this
A\ (A\B) = A\ ( A ∩ B^c )
= A ∩ ( A^C ∪ B )
= ( A ∩ A^C ) ∪ ( A ∩ B )
= Ф ∪ ( A ∩ B )
= ( A ∩ B )
ALSO : B\(B\A) = attached below is the remaining parts of the solution
B) A\ (BA) = B\(A\B) = Sometimes true and sometimes false
attached below is the prove using De Morgan's law
Answer:
Simplifying
3n + 7 + -2 = 0
Reorder the terms:
7 + -2 + 3n = 0
Combine like terms: 7 + -2 = 5
5 + 3n = 0
Solving
5 + 3n = 0
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '-5' to each side of the equation.
5 + -5 + 3n = 0 + -5
Combine like terms: 5 + -5 = 0
0 + 3n = 0 + -5
3n = 0 + -5
Combine like terms: 0 + -5 = -5
3n = -5
Divide each side by '3'.
n = -1.666666667
Simplifying
n = -1.666666667
Step-by-step explanation: