Let x=large boxes and y=small boxes.
x+y=110
60x+35y=5100
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You need to cancel out one of the variables to solve for one. Let's cancel out y.
-35(x+y=110)
-35x-35y=-3850
60x+35y=5100
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Add the two equations.
25x=1250
x=50
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Plug in 50 for x into one of the equations to solve for y.
50+y=110
y=60
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50 large boxes
60 small boxes
I’m thinking b would be it i’m not so sure
The first one because the left bound is included [ and the right one is not )
40x+8x^2=0 can be solved for x (there are two solutions):
Divide all 3 terms by the greatest common multiple (which is 8x):
40x+8x^2=0
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8x 8x
5 + x = 0 produces the root x = - 5.
Setting 8x = 0 and solving for x produces the root x = 0.
Be certain to check these results. substitute x = -5 into 40x+8x^2=0. Is the resulting equation true or false? Next, subs. x=-5 into 40x+8x^2=0. Is the resulting equation true or false?
