Answer:
The ratio of the number of female teachers to the number of male teachers is 18:5.
Step-by-step explanation:
First: Review how to write a ratio:
To write a ratio, take the two quantities, and put them on both sides of a colon (:). So, our two quantities our 18 and 5. But, they need to be in a specific order:
There are 18 female teachers and 5 male teachers at Ashley's school. What is the ratio of the number of female teachers to the number of male teachers?
Since, they mentioned the number of female teachers first, we put the quantity of female teachers first. So we will write 18 first and 5 after. So, the ratio is 18:5.
Thank you for reading
Topic: Ratios
The answer is 73.5
To make it a lot easier split the shapes into a rectangle and triangle.
The rectangle is a tad easier because the measurements are given here.
5 x 12 = 60 (rectangle area)
To find the triangle find the base then height. The base is 3cm and the height is 9cm (shown above)
9 x 3 = 27
Divide that by 2 because it's a triangle and you get 13.5.
Add those two numbers and voila you have your answer of 73.5.
Answer:
96
Step-by-step explanation:
once you fill in the Blanks that are solvable, you will work your way into the answer. For example, the first column, the missing number has to be 155-76 or 79. Now you can find your answer. In the second row, “no Laptop”, you have 79 (solved above) plus 17. So your answer is 79+17 or 96.
Answer:
1.
Part A: Yes, it is (a - b)².
Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.
Part C: x² - 12x + 36.
2.
Part A: Not a special product.
Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.
Part C: x² + 9x + 8.
3.
Part A: Yes, it is (a + b)²
Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.
Part C: 9x² + 12x + 4.
4.
Part A: Yes, it is (a + b)(a - b), a difference of squares.
Part B: a² - b² => 4x² - 49
Part C: 4x² - 49
5.
Part A: Not a special product.
Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.
Part C: 2x² - 15x + 25
Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
