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erica [24]
3 years ago
7

What is the equation of the line in standard form?

Mathematics
2 answers:
marta [7]3 years ago
7 0

Answer:

3x + 5y = 1

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Obtain the equation in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line

m = \frac{-1-2}{2+3} = - \frac{3}{5}

y = - \frac{3}{5} x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (2, - 1), then

- 1 = - \frac{6}{5} + c ⇒ c = - 1 + \frac{6}{5} = \frac{1}{5}

y = - \frac{3}{5} x + \frac{1}{5} ← in slope-intercept form

multiply all terms by 5

5y = - 3x + 1 ( add 3x to both sides )

3x + 5y = 1 ← in standard form


Fudgin [204]3 years ago
6 0

(-3, 2) & (2, -1):

  • Y2 is -1
  • Y1 is 2
  • X2 is 2
  • X1 is -3

<u>Y2 - Y1</u>

X2 - X1

<u>-1 - 2</u>

2 - - 3

<u>-3</u>

5

y - Y1 = m(x - X1)

y - 2 = -3/5(x - -3) --- POINT SLOPE FORM

y - 2 = -3/5(x + 3)

y - 2 = -3/5x - 1.8

  + 2            + 2

y = -3/5x + 0.2 --- SLOPE INTERCEPT FORM

+3/5x + 3/5x

3/5x + y = 0.2 --- STANDARD FORM


Hope this helps you!!! :)

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