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2 years ago

Round your answer to the nearest hundredth.

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

3 0

tan 35 = BC / 2

0.700 = bc/2

bc = 1.4

solmaris [256]2 years ago

3 0

Answer:

$in \: right \: angle \: triangl \: a \: b \: c \\ tan35 = \frac{bc}{ac } = \frac{bc}{2} \\ bc = 2 \times 0.7002 \\ bc = 1.4004$

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Please help!!! MAX POINTS I CAN DO i put it in math because i trust the math people more

valkas [14]

Answer:

The 1st Blank is: A pure substance, or simply a substance

The 2nd blank on the left is: Elements

The 3rd blank on the right is: Compounds

The 4th blank which is the second middle one is: A mixture

The 5th blank which is the bottom left one is: Heterogeneous mixture

The 6th blank which is the last one on the bottom right is: Homogeneous mixture

Look at the step-by-step explanation if you get confused at the bottom.

Step-by-step explanation:

The 1st Blank: I would just put a pure substance.

The 2nd blank on the left: They are three characteristics of elements but just put elements.

The 3rd blank on the right: They are three characteristics of compounds but just put compounds.

The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.

The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.

The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.

3 0

3 years ago

Read 2 more answers

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

Helpppp I don’t get the question!!!

avanturin [10]

Answer:

43.75 hope i helped you

4 0

3 years ago

How do i solve this?

vazorg [7]

Usually I would use my head, but you can use whatever you want.

3 0

2 years ago

Given: △RST ~ △VWX

tatiyna

Answer:

Given

Step-by-step explanation:

Given that: △RST ~ △VWX, TU is the altitude of △RST, and XY is the altitude of △VWX.

Comparing △RST and △VWX;

TU ~ XY (given altitudes of the triangles)

<TUS = <XYW (all right angles are congruent)

<UTS ≅ <YXW (angle property of similar triangles)

Thus;

ΔTUS ≅ ΔXYW (congruent property of similar triangles)

<UTS + <TUS + < UST = <YXW + <XTW + <XWY = $180^{0}$ (sum of angles in a triangle)

Therefore by Angle-Angle-Side (AAS), △RST ~ △VWX

So that:

$\frac{TU}{XY}$ = $\frac{US}{YW}$ (corresponding side length proportion)

4 0

3 years ago