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andreev551 [17]
2 years ago
15

Round your answer to the nearest hundredth.

Mathematics
2 answers:
Dmitry_Shevchenko [17]2 years ago
3 0

tan 35 = BC / 2

0.700 = bc/2

bc = 1.4

solmaris [256]2 years ago
3 0

Answer:

in \: right \: angle \: triangl \: a \: b \: c \\  tan35 =  \frac{bc}{ac }  =  \frac{bc}{2}  \\ bc = 2 \times 0.7002 \\ bc = 1.4004

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The speed of boat in still water is 15km/hr if needs 4 more his to travel 63 km against the current of a river than it needs to
hram777 [196]

Answer:

\frac{63}{15  - c} - \frac{63}{15  + c} = 4

Step-by-step explanation:

The systems of equations are

Let us assume the rate of the current be c

Now actual speed against the current is (15 - c)

And, the actual speed with the current is (15 + c)

Here we applied the time formula i.e. distance by speed

Also the upstream time  - downstream time = 4

Now the equations are

\frac{63}{15  - c} - \frac{63}{15  + c} = 4

5 0
3 years ago
Somebody pls help me with this question pls
monitta
292in^3
3x6x10=180 because I’ve split the shape in half
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4 0
2 years ago
Which is the graph of g(x) = [X + 3]?
Vanyuwa [196]

Answer

D or the fourth one because i took the quiz and got it right

3 0
3 years ago
Express sin A,cos A and tan A as ratios
OverLord2011 [107]

Answer:

Part A) sin(A)=\frac{2\sqrt{42}}{23}

Part B) cos(A)=\frac{19}{23}

Part C) tan(A)=\frac{2\sqrt{42}}{19}

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

sin(A)=\frac{BC}{AB}

substitute the values

sin(A)=\frac{2\sqrt{42}}{23}

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

cos(A)=\frac{AC}{AB}

substitute the values

cos(A)=\frac{19}{23}

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

tan(A)=\frac{BC}{AC}

substitute the values

tan(A)=\frac{2\sqrt{42}}{19}

8 0
3 years ago
The surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²? What is the scale factor of the smaller
max2010maxim [7]

Answer:

scale factor of the smaller  prism to the larger prism is B. 21/23

Step-by-step explanation:

Given

surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²?

scale factor is ratio of sides of two similar objects

thus scale factor for given prism will be = side of smaller prism / side of larger prism

in general rule

If shape of solid has scale factor of k

scale factor of area = k²

scale factor of volume = k³

_____________________________

Given in the problem area of two prism is given

we know area = side^2

scale factor of area = k²

k^2 = area of smaller prism / area of larger prism

k^2 = 882 / 1058 = 441/529\\k = \sqrt{ 441/529} \\k = 21/23

Thus, correct option is B 21/23.

7 0
3 years ago
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