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3 years ago

4b-4=3b+4 solve for b

Mathematics

2 answers:

damaskus [11]3 years ago

6 0

Answer:

4b-3b=4+4

b=8

Step-by-step explanation:

Hence, the value of b is 8

#hope it helps

natima [27]3 years ago

5 0

Answer:

b=8

Step-by-step explanation:

4b-4=3b+4

You have to add 4 to both sides so that all the like terms are together

4b=3b+8

Then you subtract 3b from each side so that the like terms are all together

b=8

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3 years ago

the probability of rolling a 6 on a biased dice is 1/5 1) complete the tree diagram. 2) Work out the probability of rolling two

pickupchik [31]

Answer:

Step-by-step explanation:

Not 6 on all rolls in the diagram = 4/5

6 on all rolls in the diagram is 1/5

To find the probablity of rolling two sixes, 1/5 x 1/5 = 4/100 = 0.04 = 4%

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3 years ago

Harold weighs 270 pounds now. If Harold goes on a diet and loses 30 pounds, then how many kilograms will he weigh?

Leto [7]

Answer:

108.862 kg

Step-by-step explanation:

270lb -30lb =240 lb

240 lb is approx. 108.862 Kg

(Pounds are approx 2.205 times Kg)

<em>I hope this helps! :)</em>

3 0

3 years ago

Read 2 more answers

two friends bought a $14 pizza. Each person bought their own drink. The total cost of the food can be represented by the express

yanalaym [24]

The expression might be x=7

4 0

2 years ago

A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len

aniked [119]

Answer:

a. V = (20-x) $x^{2}$ $in^{3}$

b . 1185.185 $in^{3}$

Step-by-step explanation:

Given that:

The height: 20 - x (in )
Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h * $x^{2}$ $in^{3}$

<=> V = (20-x) $x^{2}$ $in^{3}$

b. What is the maximum possible volume of the box?

To maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3 $x^{2}$ + 40x

Let dV / Dx = 0, we have:

-3 $x^{2}$ + 40x = 0

<=> x = 40/3

=>the height h = 20/3

So the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 $in^{3}$

7 0

2 years ago