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Aleks [24]
3 years ago
14

4b-4=3b+4 solve for b

Mathematics
2 answers:
damaskus [11]3 years ago
6 0

Answer:

4b-3b=4+4

b=8

Step-by-step explanation:

Hence, the value of b is 8

#hope it helps

natima [27]3 years ago
5 0

Answer:

b=8

Step-by-step explanation:

4b-4=3b+4

You have to add 4 to both sides so that all the like terms are together

4b=3b+8

Then you subtract 3b from each side so that the like terms are all together

b=8

You might be interested in
The curve with the equation y=8x^2 + 2/x has one turning point.
anyanavicka [17]

Answer:

(1/2, 6).

Step-by-step explanation:

Turning points in a graph may exist whenever the derivative equals 0. Hence, let’s differentiate and then solve our function.

We have:

\displaystyle y=8x^2+\frac{2}{x}

Take the derivative of both sides with respect to x:

\displaystyle y^\prime=16x-\frac{2}{x^2}

Simplify:

\displaystyle y^\prime=\frac{16x^3-2}{x^2}

We will now set this equal to 0 and solve for x. Hence:

\displaystyle \begin{aligned} 0&=\frac{16x^3-2}{x^2} \\ 0&=16x^3-2 \\ 2&=16x^3 \\ \frac{1}{8}&=x^3 \\ \frac{1}{2}&=x \end{aligned}

Hence, the graph turns at x=1/2. This is the x-coordinate.

Then it follows that the y-coordinate will be:

\displaystyle{\begin{aligned} y&=8(\frac{1}{2})^2+\frac{2}{\frac{1}{2}} \\ y&=8(1/4)+2(2) \\ y&=2+4 \\ y&=6\end{aligned}

Hence, our coordinate Is (1/2, 6).

8 0
3 years ago
ANSWER ASAP 30 POINTS GIVEN
Montano1993 [528]
Answer is B.
it's parallelogram and opposite sides are congruent.
--------------------------
4 0
4 years ago
Read 2 more answers
Assume ​Y=1​+X+u​, where X​, Y​, and ​u=v+X are random​ variables, v is independent of X​; ​E(v​)=0, ​Var(v​)=1​, ​E(X​)=1, and
kobusy [5.1K]

Answer:

a) E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1+

b) E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2

c) E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2

d) E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6

e) E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1

f) E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3

g) E(u) = E(v) +E(X) = 0+1=1

h) E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

Step-by-step explanation:

For this case we know this:

Y = 1+X +u

u = v+X

with both Y and u random variables, we also know that:

[tex] E(v) = 0, Var(v) =1, E(X) = 1, Var(X)=2

And we want to calculate this:

Part a

E(u|X=1)= E(v+X|X=1)

Using properties for the conditional expected value we have this:

E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1

Because we assume that v and X are independent

Part b

E(Y| X=1) = E(1+X+u|X=1)

If we distribute the expected value we got:

E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2

Part c

E(u|X=2)= E(v+X|X=2)

Using properties for the conditional expected value we have this:

E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2

Because we assume that v and X are independent

Part d

E(Y| X=2) = E(1+X+u|X=2)

If we distribute the expected value we got:

E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6

Part e

E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1

Part f

E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3

Part g

E(u) = E(v) +E(X) = 0+1=1

Part h

E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

8 0
3 years ago
Which expression is equivalent to 3(-4x - 5)?
REY [17]
The answer would be 12x-15
7 0
3 years ago
Read 2 more answers
Someone help I will give u 5 points
SCORPION-xisa [38]
83 would be the answer. You don’t gotta multiply or anything
3 0
3 years ago
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