The solution to the system of equation is as follows:
x = 3
y = 11
<h3>How to solve the system of equation?</h3>
y = x + 8
y = 3x + 2
Using substitution method,
3x + 2 = x + 8
subtract x from both sides
3x - x + 2 = x - x + 8
2x + 2 = 8
subtract 2 from both sides
2x + 2 - 2 = 8 - 2
2x = 6
divide both sides by 2
2x / 2 = 6 / 2
x = 3
y = 3 + 8 = 11
y = 11
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The diamter of Jupiter is 11 times that of the earth, so the radius is also 11 times that of the earth. You have to just square 11 to get 121 times
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Answer:
E is not a subspace of
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
Y = 1 + i
<span>(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i </span>
<span>(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i </span>
<span>1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i </span>
<span>1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i </span>
<span>-3 - 4i + k = -i </span>
<span>k = 4i - i + 3 </span>
<span>k = 3i + 3 </span>
<span>k = 3 * (1 + i) </span>
<span>k = 3y</span>
the answer for this would be the last one. two rays that meet at a end point.
hope this helps!