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pshichka [43]
3 years ago
7

Three cards are drawn with replacement from a standard deck. what is the probability that the first card will be a diamond, the

second card will be a black card, and the third card will be a face card
Mathematics
1 answer:
svlad2 [7]3 years ago
6 0
507/17576 or 0.0288 

you take all the probabilities separate then multiply them all together. Then Simplify
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Step-by-step explanation:

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It is four. So two and two you add them together to be four. Good job. Your learning :)
4 0
3 years ago
Please show work! will mark brainlest!!!!!!!!
GarryVolchara [31]

Answer:

34cm

4+2+5+9+6+3+3+(9-4+3)

6 0
2 years ago
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Select the slope-intercept form of an equation for a line with y-intercept -2 and slope 6.<br>​
ozzi

Answer:

y = 6x - 2

Step-by-step explanation:

slope intercept form is y = mx + b

m = slope

b = y-intercept

They give us the slope (m) which is 6 and the y-intercept (b) which is -2. PLug it into the equation

y = mx + b

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3 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
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