A rubber ball is bounced from a height of 9 meters and bounces continuously .Each successive bounce reaches a height that is a t
2 answers:
Answer:
1/81 meters
Step-by-step explanation:
Since it reaches a height of 1/3 the previous height after each bounce, we can set up an equation for "y", the balls height, after x bounces:
Therefore, to find the ball's height after 6 bounces we just plug-in 6 for x in the equation above to get 1/81.
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Answer:
Step-by-step explanation:
Consider the graphs of the and
.
By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.
then
o
. Therefore the integration limits are:
and
The inverse functions are given by:
and
. Then
The volume of the solid of revolution is given by:
Answer:
The value of x = 0.41
Step-by-step explanation:
∵
Let
∴
∴ 6y² - 5y = 6
∴ 6y² - 5y - 6 = 0 ⇒ factorize
∴ (3y + 2)(2y - 3) = 0
∴ 3y + 2 = 0 ⇒ 3y = -2 ⇒ y = -2/3
∴ 2y - 3 = 0 ⇒ 2y = 3 ⇒ y = 3/2
∵
∴ ⇒ refused
( never gives -ve values)
∵ ⇒ insert <em>ln</em> in both sides
∵ ⇒ <em>ln</em>(e) <em>= 1</em>
∴
∴ x = ln(3/2) = 0.41
<em>Answer: </em>
<em>y = </em><em>
− 7 x 3 −
2</em>
<em />
<em>Step-by-step explanation:</em>
<em>you gotta work backwards to find the factors from the roots then multiply the factors together.</em>