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3 years ago

7

Consider the equation:-3+x=n. If n is positive, what must be true about x? Explain your answer? Include a possible value of x in

your explanation??? Plzzz

1 answer:

Julli [10]3 years ago

5 0

Answer:

X must be a number more than 3

X could be 5

Step-by-step explanation:

If x was 5, -3+5 would equal 2. This is a positive number.

If we said that X was a negative number such as -4, it would not work because -3-4=-7. That means that X equals -7. This is not a valid answer as it is a negative number.

This was just a guess, please check.

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Find an equation of the plane that is parallel to the line of intersection of the planes ( x + 3y + z = 3 ) ( 3x - y - z = 0 ) a

NeTakaya

Answer:

Wow I got the first step

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intersection of the line perpendicular

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3 years ago

Find the seventh term of the

jekas [21]

Answer:

$T_7 = \frac{64}{729}$

Step-by-step explanation:

Given

$a =1$

$r = \frac{2}{3}$

Required

Determine the 7th term

The nth term of a gp is:

$T_n = a * r^{n-1$

So, we have:

$T_7 = 1 * \frac{2}{3}^{7-1$

$T_7 = 1 * \frac{2}{3}^{6$

$T_7 = 1 * \frac{2^6}{3^6}$

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$T_7 = \frac{64}{729}$

6 0

3 years ago

I need help with this math question

ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

$\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}$

Step 2: Place a logarithm base 7 on both sides

$7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}$

Step 3: Solve for x

$\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5$

Neat exponent question :)

7 0

2 years ago

Look at the system of equations below.

Paul [167]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=-1$

Step-by-step explanation:

Considering the system of the equation

$\begin{bmatrix}y=-2x+3\\ 4x-3y=11\end{bmatrix}$

$\mathrm{Subsititute\:}y=-2x+3$

$\begin{bmatrix}4x-3\left(-2x+3\right)=11\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:4x-3\left(-2x+3\right)=11$

$4x-3\left(-2x+3\right)=11$

$4x+6x-9=11$

$10x-9=11$

$10x-9+9=11+9$

$10x=20$

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$\mathrm{For\:}y=-2x+3$

$\mathrm{Subsititute\:}x=2$

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$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

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3 years ago

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balandron [24]

Answer: m

Step-by-step explanation:

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3 years ago