I HAVE 10 MIN LEFT CAN SOMEONE HELP ME WITH A FEW OF THESE OR ALL OF EM?

When twotwo basketball players are about to have a free-throw competition, they often draw names out of a hat to randomly selec

erica [24]

There are 2! = 2 ways to arrange the names of two basketball players in a hat.

Since, the are going to throw alphabetically, there is 1 way for the names to be arranged alphabetically.

Therefore, <span>the probability that they shoot free throws in alphabetical order is $\frac{1}{2} = 0.5$ </span>

6 0

3 years ago

Derek says that the quotient of -2/7 divided by -2/21 is -1/3. Part A: What is the correct quotient? Part B: What mistake did De

Thepotemich [5.8K]

Answer:

The correct quotient is 3.

I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ .

Step-by-step explanation:

We have to check the quotient of $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

Part A:

Now, $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

= $\frac{-\frac{2}{7} }{-\frac{2}{21} } =3$

So, the correct quotient is 3.

Part B:

Derek says that the quotient is $-\frac{1}{3}$ .

So, I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ . (Answer)

8 0

3 years ago

Emmett participated in a race. During the race, he ran 5 miles north and then ran 12 miles west. What is the shortest distance t

Lelechka [254]

I'd suggest you sketch this situation. If you did, you'd likely see right away that the shortest distance back to the starting point would be the hypotenuse of the right triangle whose legs are of lengths 5 miles and 12 miles.

Apply the Pythagorean Theorem to solve this.

4 0

3 years ago

PLS HELP ASAP PLSSS PLSSS FIRST CORRECT ANSWER GETS BRAINLIEST PLS ANSWER

anzhelika [568]

Answer:

√(23)

Step-by-step explanation:

The Pythagorean Theorem is a² + b² = c²

so...

a = 7

b = 3

7² + 3² = c²

14 + 9 = c²

√(23) = c

PLEASE RATE!! I hope this helps!!

If you have any questions let me know

7 0

2 years ago

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago