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3 years ago

Observe the table. How many times greater must the acceleration of Object B be than the acceleration of

Mathematics

1 answer:

gulaghasi [49]3 years ago

3 0

Answer:

Step-by-step explanation:

You first start by finding the acceleration of the problem.

a=f/m

Which this case is 45.

The question is asking " How many times greater must it be than A?"

You then divide

45/9

Your final answer is 5.

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(01.05) Use the graph below to answer this question: graph of line going through negative 1, 4 and 2, 0 Find the average rate of

dsp73

1) Find the graph of a line passing through (-1, 4) and (2, 0).

The slope of two points can be determined by dividing the difference of y-values by the difference of x-values:

$\frac{4-0}{-1-2} =\frac{4}{-3}$

The slope of this equation is -4/3. Inputting this into the slope-intercept form of an equation, we get:

$y=\frac{-4}{3} x+b$

To find b, substitute x and y for one of the given coordinate pairs:

0 = (-4/3)(2) + b

0 = -8/3 + b

8/3 = b

Substitute the b value into the equation to finish the line:

$y=\frac{-4}{3} x+\frac{8}{3}$

4 0

3 years ago

Read 2 more answers

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the

Kazeer [188]

Answer:

$m=-\frac{1}{6}$

$b=5$

Step-by-step explanation:

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-6,\:6\right),\:\left(x_2,\:y_2\right)=\left(12,\:3\right)$

$m=\frac{3-6}{12-\left(-6\right)}$

$m=-\frac{1}{6}$

As the equation in point-slope form

$y-y_1=m\left(x-x_1\right)$

Here:

m is the slope and

$\left(x_1,\:y_1\right)$ is a point on the line

using $m=-\frac{1}{6}$ and $\left(x_1,\:y_1\right)=\left(-6,\:6\right)$ then

$y-6=-\frac{1}{6}\left(x-\left(-6\right)\right)$

$-\frac{1}{6}\left(x-\left(-6\right)\right)=y-6$

$\mathrm{Multiply\:both\:sides\:by\:}-6$

$\left(-\frac{1}{6}\left(x-\left(-6\right)\right)\right)\left(-6\right)=y\left(-6\right)-6\left(-6\right)$

$x+6=-6y+36$

$x+6-36=-6y$

$x-30=-6y$

$\frac{x-30}{-6}=\frac{-6y}{-6}\:$

$y=\frac{-1}{6}x+5$

Thus

$y=\frac{-1}{6}x+5$

comparing the equation with the slope-intercept form

$y=mx+b$

so,

$y=mx+b$

$y=\frac{-1}{6}x+5$

Therefore,

$m=-\frac{1}{6}$

$b=5$

5 0

4 years ago

Read 2 more answers

PLEASE HELP <br> I forgot how to do this and it’s for a final :((

natima [27]

F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4 g(4) -(4)2-12 = -16-12= -28

8 0

4 years ago

A new skateboard cost $150. You have a 30% off coupon how much money did you save with your coupon?

insens350 [35]

150 x .30 = 45

You saved $45 if you use the coupon for the skateboard

5 0

4 years ago

How to do the problem

trapecia [35]

Step-by-step explanation:

$g(0.5) = 2 \\ \\ h(x) = g(x).f(x) \\ \therefore \: h(2) = g(2).f(2) \\ \therefore \: h(2) = 5 \times 2\\ \therefore \: h(2) = 10\\ \\ \\ j(x) = g(x) - f(x) \\ \therefore \: j(4) = g(4) - f(4) \\ \therefore \: j(4) = 9 - 8\\ \therefore \: j(4) = 1\\ \\ \\$

4 0

3 years ago