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Neko [114]
3 years ago
10

Round 7,298,341 to the nearest 10,000

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0

8,300,000 is your answer because 8 is higher then five so you add one to 9 which make it ten so u have to add one more to 200,000
Salsk061 [2.6K]3 years ago
5 0

Answer:

8,300,000

Step-by-step explanation:

8,300,000 is your answer because 8 is higher then five so you add one to 9 which make it ten so u have to add one more to 200,000 You Can Also Use Rouning Caulator But Any Ways Hope This Helped Uwu Aw

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What is 5.16 divided by 0.6 (pls show work)
IrinaVladis [17]

Answer:

8.6

Step-by-step explanation:

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6 0
2 years ago
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Cody must complete 125 credit hours of instruction. If he has completed 60% of his requirement, how many credits did Cody comple
umka2103 [35]
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4 years ago
In an experiment, a coin is flipped 600 times. The coin landed on tails 272 times. Which of the following statements is true?
balandron [24]

Answer:i feel like its most likely gonna be the last one

Step-by-step explanation:

3 0
3 years ago
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In how many ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other?
balandron [24]
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
</span>
So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
</span>
<span>=====================================================
</span>
<span>Another solution:
</span>
<span>If ann seated in one of the ends, the number of ways = 3*2
</span>
<span>If ann didn't seat in one of the ends , the number of ways = 2*3
</span>
So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
</span></span>
The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
7 0
3 years ago
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