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Charra [1.4K]
3 years ago
7

Carson bought 2.5 pounds of gummy bears for $2.75 per pound. How much did he spend on gummy bears? (Round your answer to the nea

rest hundredths place.) Please help meeeeeeee
Mathematics
1 answer:
Amanda [17]3 years ago
5 0
Since this number has a decimal. Break the answer apart. 2.75•2=$5.50. That would be for two pounds. For another additional 0.5 pounds, you would divide $2.75/2= 1.375. This would be rounded up to 1.38. Now you add 5.50+1.38=$6.88
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Find the surface area of the given prism​
Wewaii [24]

Answer:

Hello! answer: 432

Step-by-step explanation:

12 × 8 = 96

12 × 8 = 96

12 × 6 = 72

12 × 6 = 72

8 × 6 = 48

8 × 6 = 48

Then you add them all up so...

96 + 96 + 72 + 72 + 48 + 48 = 432 therefore the surface area is 432 hope that helps!

3 0
3 years ago
Hot dogs are soo in packages of 8 and hot dog buns are sold in packages of 12. What is the smallest number of each that could be
ale4655 [162]
D 24

12 times 2 equals 24
8 times 3 equals 24
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3 years ago
Carter needs to wrap 7 presents outfit and says if I make 6 equal safe pieces I'll have just enough pieces I can use one piece f
Black_prince [1.1K]
Yes he does have enough
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3 years ago
Read 2 more answers
Simplify the following<br> x=<br> -(-10) /(-10)2 - 4(1)(2)<br> 2(1)
ollegr [7]

This equation simplified would be

x= -5/18

8 0
3 years ago
The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard
MA_775_DIABLO [31]

a. This information is given to you.

b. We want to find

\mathrm{Pr}\{X > 8.9\}

so we first transform X to the standard normal random variable Z with mean 0 and s.d. 1 using

X = \mu + \sigma Z

where \mu,\sigma are the mean/s.d. of X. Now,

\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}

where \Phi(z) is the CDF for Z.

c. The 76th percentile is the value of X=x_{76} such that

\mathrm{Pr}\{X \le x_{76}\} = 0.76

Transform X to Z and apply the inverse CDF of Z.

\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76

\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)

\dfrac{x_{76} - 10.5}2 \approx 0.7063

x_{76} - 10.5 \approx 1.4126

x_{76} \approx \boxed{11.9126}

5 0
2 years ago
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