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ziro4ka [17]
3 years ago
9

Hello, can you please express this without denominators with the work?

Mathematics
1 answer:
Lena [83]3 years ago
5 0
\bf  a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
%  negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-----------------------------\\\\
\cfrac{4xy}{mn^5}\implies \cfrac{4xy}{1}\cdot \cfrac{1}{m^1}\cdot \cfrac{1}{n^5}\implies 4xym^{-1}n^{-5}

notice, all you do is, move the factor from the bottom to the top, or from the top to the bottom, and the sign changes, from negative to positive or the other way around, is all there's on that
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Which line is perpendicular to a line that has a slope of 1/2?​
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Answer:

line HJ, because line with slope 1/2 is AB=2/4=1/2.

AB is perpendicular to HJ, because it forms right angle

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You were given the polynomial f(x)=3x^3+13x^2+19x+k and you know that f(-2)=0find k
eduard

Answer:

k = 10

Explanation:

The initial polynomial is:

f(x)=3x^3+13x^2+19x+k

If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:

\begin{gathered} f(-2)=3(-2)^3+13(-2)^2+19(-2)+k=0 \\ 3(-2)^3+13(-2)^2+19(-2)+k=0 \end{gathered}

Therefore, we can solve for k as follows:

\begin{gathered} 3(-8)+13(4)+19(-2)+k=0 \\ -24+52-38+k=0 \\ -10+k=0 \\ -10+k+10=0+10 \\ k=10 \end{gathered}

So, the value of k is 10

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3 years ago
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Alonzo wrote the equation x = 2+4y-5. Which equation is equivalent?
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Consider the equation x = 2+4y-5, it can be expressed as x = 4y-3.

Now, we have to write the equivalent equation.

Since, Equivalent equations are those equations which have exactly same solution. We can say that the two equations are equivalent if solution of one equation is the solution of other equation.

So, consider the equation x = 4y -3

Equivalent equation can be obtained by multiplying the given equation by any number say '2'.

Multiplying both sides of the given equation by '2'.

x = 4y-3

2 \times x = 2 \times (4y-3)

2x = (2 \times 4y)-( 2 \times 3)

2x = 8y-6 is the required equivalent equation.

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3 years ago
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