I think the answer is x=60
I just solved this one
anothe way is undistribute the 2 first and move -14 to side
2(x^2+6x)-14=0
comlete the squer inside and add negative
2(x^2+6x+9-9)-14=0
factor perfect square
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
add 32 both sides
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=-4-3 or 4-3
x=1 or -7
answer is C
So what we do is we splie it up
remember that 1/1=1 so therefor 6/6=1
find out how many 6/6 are in 23 and how much is left over
remember that you can add the top numbers if the bottom numbers are the same
23/6-6/6=17/6 (that's one)
17/6-6/6=11/6 (that's 2)
11/6-6/6=5/6 (that's three)
therefor you have
23/6=6/6+6/6+6/6+5/6=1+1+1+5/6=3+5/6=3 and 5/6
therfor 3 goes in the blank in front of the 5/6
